Subtract 5-3 1/3 fraction

Answers

Answer 1

Answer: 5 = 15/3

3 1/3 = 10/3

15/3 - 10/3 = 5/3

so 5-3 1/3 is either 5/3 or 1 2/3.

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Mofor had $21 to spend on two notebooks. After buying them he had $13. How much did each notebook cost?

Answers

His total cost was 8 dollars, so you divide that by two.

8/2 = 4

So, each notebook was $4.00.

PLEASE HELP ill Mark BRAINLIEST 31 points too

Answers

Answer:(-1,7)

Step-by-step explanation:

Factor 26r3s + 52r5 – 39r2s4. What is the resulting expression? 13(2r3s + 4r5 – 3r2s4)
13r2s(2r + 4r3 – 3s3)
13r2(2rs + 4r3 – 3s4)
13r2(26r3s + 52r5 – 39r2s4)

Answers

Answer:

Option 3rd is correct

$13r^2(2rs+4r^3-3s^4)$

Step-by-step explanation:

GCF (Greatest common factor) is the largest number that divides the two number.

Factor $26r^3s+52r^5-39r^2s^4$

Find the GCF of the given expression.

GCF of $26r^3s$ , $52r^5$ and $39r^2s^4$ is, $13r^2$

then;

$13r^2(2rs+4r^3-3s^4)$

Therefore, the resulting expression is, $13r^2(2rs+4r^3-3s^4)$

Answer:

The Given Expression is

→ $26r^3s + 52r^5 -39r^2s^4\n13* 2* r* r^2 * s + 13* 2* 2* r^2* r^2* r- 13 * 3* r^2* s * s^3\n\n\text{Taking out common factors}\n\n13r^2(2 rs + 2* 2 r^3 -3 s^4)\n\n13r^2(2 r s+ 4 r^3 - 3 s^4)$

Option $<strong>13r^2(2 rs + 4 r^3 - 3 s^4)$ is correct option.

Calculate the perimeter of the quadrilateral 2 cm 3 cm 2 cm 5 cm is it A. 10 cm B. 12 cm C. 24 cm D. 60 cm

Answers

P = 2 + 3 + 2 + 5 , where P is the perimeter;
P = 12 cm;
The correct answer is B.

A professional quarterback passed for 4,384 yards in 16 games in one football season. If he passed for the same number of yards each game, how many yards did he pass for in each game? Enter your answer in the box.

Answers

274 yards per game
hope this helps

Dena's softball team can win (W) or lose (L) each game. Which of the following are elements in the sample space for 2 softball games?

Answers

In a softball game, the odds are only win or lose the game. When 2 games are already being considered, the elements in the sample space are already 2 in each set. The sets are {W,W}, {W,L}, {L,W} and {L,L}. Hence, there are 4 sets all in all to describe the odds of the two games.

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