2.00 g of PbCl2 at 80°C
100.2 g of NaNO3 at 60°C
128 g of KI at 0°C
75.5 g of LiCl at 20°C
8.22 g of Ba(OH)2 at 40°C
Answer:
1) unsaturated
2) unsaturated
3) saturated
4) unsaturated
5) saturated
Explanation:
A solution with solute that dissolves until it is unable to dissolve anymore, leaving the undissolved substances at the bottom., is called saturated. Each solution has a certain amount of mass that can dissolve at certain temperature.
A solution with less solute than the saturated solution, that completely dissolves, leaving no remaining substances., is called unsaturated.
A solution ,with more solute than the saturated solution, that contains more undissolved solute than the saturated solution, is called oversaturated.
A) 2.00 g of PbCl2 at 80°C
⇒ At 80 °C this solution is saturated when there is 2.54 grams of PbCl2 in solution
2.00 < 2.54 This solution is unsaturated
B) 100.2 g of NaNO3 at 60°C
⇒ At 60 °C this solution is saturated when there is 122 grams of NaNO3 in solution
100.2 < 122
This solution is unsaturated
C) 128 g of KI at 0°C
⇒ At 0 °C this solution is saturated when there is 128 grams of KI in solution
This solution is saturated
D) 75.5 g of LiCl at 20°C
⇒ At 20 °C this solution is saturated when there is 83.5 grams of LiCl3 in solution
75.5 < 83.5
This solution is unsaturated
E) 8.22 g of Ba(OH)2 at 40°C
⇒ At 40 °C this solution is saturated when there is 8.22 grams of Ba(OH)2 in solution
This solution is saturated
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To find the molecular formula from the empirical formula, first calculate the empirical formula mass. Then, divide the molecular or molar mass by the empirical formula mass to find the number of empirical formula units per molecule. Finally, multiply the subscript of each element in the empirical formula by this number to get the molecular formula.
The process of finding the molecular formula from the empirical formula involves a few steps. First, you need to determine the empirical formula of a compound, which is the simplest positive integer ratio of atoms present in a compound. After you have the empirical formula, you can calculate the empirical formula mass by summing up the average atomic masses of all the atoms in the empirical formula.
Next, compare the compound's molecular or molar mass (which you should know or have been given) to the empirical formula mass. This comparison is done by dividing the molecular or molar mass by the empirical formula mass. This will give you the number of empirical formula units, denoted as n, per molecule of the compound.
The final step is to take the empirical formula and multiply the subscript of each element in it by n. This will give you the molecular formula of the compound.
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Metal oxides M2O, peroxide M2O2, and superoxide MO are produced by alkali metals. Metal oxide is also referred to as basic oxide since basic hydroxide is the end result of interactions between metal oxide and water. As a result, their combination with acid produces salt and water in a manner similar to a regular acid-base reaction.
One of the most significant and well-characterized solid catalysts is metal oxide. Metal oxides are used in acid-base and redox processes and are regarded as heterogeneous catalysts.
Several metals are separated from their naturally occurring compounds like oxide and chloride using a breakdown reaction.
Metal oxides are crucial in various additional applications, such as energy production, conversion, and storage, as well as in environmental remediation and pollution monitoring.
Because they react with weak acids to produce salt and water, metallic oxides are basic in nature. They further react with water to create metal hydroxides, which are naturally alkaline due to the production of OH- ions in solution.
Thus, Metal oxides M2O, peroxide M2O2, and superoxide MO are produced by alkali metals.
To learn more about metal oxide, follow the link;
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2) 0.101 kg Ti into atoms
Answer:
The answer to your question is below
Explanation:
1) 0.143g of Mg into atoms
- Look for the atomic number of Magnesium in the Periodic table
Atomic number = 24.31 g
-Use the Avogadro's number to find the number of atoms
24.31g ------------------- 6.023 x 10²³ atoms
0.143 g ----------------- x
x = (0.143 x 6.023 x 10²³) / 24.31
x = 8.613 x 10²² / 24.31
x = 3.54 x 10²¹ atoms
2) 0.101 kg of Ti into atoms
-Look for the atomic number of Titanium in the Periodic table
Atomic number = 47.87 g
-Use the Avogadro's number to find the number of atoms
47.87 g --------------------- 6.023 x 10²³
101 g ---------------------- x
x = (101 x 6.023 x 10²³) / 47.87
x = 6.08x 10²⁵ / 47.87
x = 1.27 x 10²⁴ atoms
Answer:
Explanation:1 mole is equal to 1 moles CaCO3, or 100.0869 grams.