The area tjhat he can cover with these tiles is 77 ¹¹/₃₂ in²
To solve the above questions, we need to recall some of the formulas as follows:
Area of Square = (Length of Side)²
Perimeter of Square = 4 × (Length of Side)
Area of Rectangle = Length × Width
Perimeter of Rectangle = 2 × ( Length + Width )
Area of Rhombus = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Rhombus = 4 × ( Length of Side )
Area of Kite = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Kite = 2 × ( Length of Side₁ + Length of Side₂ )
Let us now tackle the problem !
Given:
Number of Tiles = N = 9 tiles
Length of Tiles = L = 3¹/₈ inches
WIdth of Tiles = W = 2³/₄ inches
Unknown:
Total Area = A = ?
Solution:
Area of One Tile.
Total Area.
Grade: College
Subject: Mathematics
Chapter: Two Dimensional Figures
Keywords: Perimeter, Area , Square , Rectangle , Side , Length , Width
Answer:
Chuck travels as 63mph
Step-by-step explanation:
Answer:
C = 65.97 in; r = 10.5 in
Step-by-step explanation:
The circumference is C = πd. Since the diameter is 21 in, the circumference is C = (3.14)(21 in) = 65.97 inches.
The radius is half the diameter:
r = (21 in) / 2 = 10.5 in
Answer:
4.45833333
Step-by-step explanation: