Green eyes.
Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
Answer:The answer is 15.78
Step-by-step explanation:
Answer:
22.84 yep
Step-by-step explanation:
c. mean: 46.85 median: 47 mode: none
b. mean: 46.85 median: 47 mode: 10, 47, 93
d. mean: 47 median: 46.85 mode: none
The mean of the given data is 46.85.
The mode of the given data is 47.
The median of the given data is 10, 47 and 93.
The mean is the mathematical average of a set of two or more numbers.
mean = sum of the given numbers/ total number of numbers
Median is the middle number is a sorted list of the numbers.
for odd number of observations
Median = {(n + 1)/2}th term
for even number of observations
Median = [(n/2)th term + {(n/2)+1}th term}/2
where, n is the number of observations
The mode is the value that is repeatedly occurring in a given set or data.
According to the given question
we have a data
78, 31, 47, 51, 16, 58, 60, 10, 30, 40, 46, 63, 65, 10, 93, 22, 13, 47, 64, 93
Arranging the given data in ascending order
10, 10, 13, 16, 22, 30, 31, 40, 46, 47, 47, 51, 58, 60, 63, 64, 65, 78 , 93, 93
Mean = (10+10+13+16+22+30+31+40+46+47+47+51+58+60+63+64+65+78+93+93)/20 = 937/20 = 46.85
Median =[(20/2)th term + {(20/2)+1}th term}]/2 = (10th term +11term)/2
= (47+47)/2 =47
Mode = 10, 47 and 93
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