I dont understand it please help i am really confused

Answers

Answer 1

Answer:

1.89 * 10^12 is a number written in scientific notation. To write a number in scientific notation, you write a number that is 1 or greater and less than 10, and then multiply it by 10 raised to an integer.

1.89 is the number from 1 to under 10.

12 is the integer exponent of 10.

The calculator writes 1.89 * 10^12, the number in scientific notation, as 1.89E12.

Again, 1.89 is the number from 1 to under 10, and 12 is the exponent. The E shows that the number after it is the exponent.

To write 1.89 * 10^-12, the calculator would write 1.89E-12.

The E stands for the exponent of 10 in scientific notation.

Related Questions

Consider the parts of the word percent. Why do you think a number out of 100 is called a percent?
A vase is in the shape of a cone that is 10 inches tall and with a diameter of 3 inches. What is the greatest amount of water the vse can hold?
Which ratio is equivalent to 3/20
what is 7/5 as a decimal number
How do I solve this problem

16% of 95 is what number?

Answers

16% of 95 is equal to 15.2

IT would be 15.2. :)

Write the equation in standard form: 3x-9=7y

Answers

If in standard form you mean slope intercept form, then you are looking to create an equation that looks like this:

y = mx + b

So you need to move around the numbers whilst keeping both sides equivalent.

3x - 9 = 7y
7y = 3x - 9
y = (3x)/7 - 9/7

Your answer should look like this:

y = (3x)/7 - 9/7

If this is not what you meant by standard form please comment and I will see if I can adjust the answer.

Sketch the quadratic function f(x) = x2 + 4x + 3. Which key feature of the graph is given incorrectly?A) minimum (-2, -1)
B) y-intercept (0, 2)
Eliminate
C) x-intercept (-3, 0)
D) x-intercept (-1, 0)

Answers

Answer:

Step-by-step explanation:

x-intercepts:

factor the function

f(x)=(x+3)(x+1)

zeros at x=-3,-1

x-intercepts --> (-3,0),(-1,0)

y-intercepts:

set x=0 in f(x)

f(0)=(0)^2+4(0)+3=3

y-intercept --> (0,3)

find minimums and maximums

The max or min of a quadratic function occurs at x=-b/(2a). If a is negative, the max value of the function is f(-b/(2a)). if a is positive, the minimum value of the function is f(-b/(2a)).

f(x)=ax^2+bx+c

f(x)=x^2+4x+3

here a is positive so you are looking for a minimum,

x=-b/(2a)

x=-4/(2*1)

x=-2 ----> plug into f(x), f(-2)=(-2)^2+4(-2)+3=-1

minimum (-2,-1)

Answer:B

Step-by-step explanation:

Kali trains for a race by running around a track. Each lap around the track is 400 METERS. She runs 4 KILOMETERS each day. How many laps around the track does Kali run in 3 days?

Answers

First step, is to work out how many laps she runs in 1 day.
To do this, we divide what she runs in one day, by the length of one lap
4km / 400m
TO make this easier, we change to units of one number to make them both the same
We will turn them both into meters
4km = 4000m (1km is equal to 1000m, therefore we multiply by 1000)

4000/400 = 10 laps per day

Now we want to find out how many laps are completed in 3 days
If 1 day is equal to 10 laps and we want 3 days, we multiply 10 laps by 3 days
10 x 3 = 30 laps

Kali runs 30 laps in 3 days

30 laps each day.................................

Explain how you know that 7/12 is greater than 1/3 but less than 2/3?

Answers

The easiest way to compare fractions is by having a common denominator for both fractions.

This is because, when the denominator is the same in both fractions, we will simply compare the numerators and the greater fraction will be the one having greater numerator

Part 1:

The first given fraction is $(7)/(12)$

The second given fraction is $(1)/(3)$

We can make the denominator in the second one equal to 12 by multiplying it by 4.

However, to preserve the value of the fraction, we will multiply it by $(4)/(4)$

This will give us:

$(1)/(3)$ * $(4)/(4)$ = $(4)/(12)$

Now, the two fractions became $(4)/(12)$ and $(7)/(12)$

The denominator is the same, so we will compare numerators.

Since 7 is greater than 4, therefore:

$(7)/(12)$ is the greater fraction

Part 2:

The first given fraction is $(7)/(12)$

The second given fraction is $(2)/(3)$

We can make the denominator in the second one equal to 12 by multiplying it by 4.

However, to preserve the value of the fraction, we will multiply it by $(4)/(4)$

This will give us:

$(2)/(3)$ * $(4)/(4)$ = $(8)/(12)$

Now, the two fractions became $(8)/(12)$ and $(7)/(12)$

The denominator is the same, so we will compare numerators.

Since 8 is greater than 7, therefore:

$(8)/(12)$ is the greater fraction

Hope this helps :)

7/12
1/3=4/12
2/3=8/12

7/12>1/3
7/12<2/3

Help please! this is due tomorrow so please help out! will mark as brainiest!!

Answers

Answer:

$\large\boxed{\bold{Q1}\ -(128)/(9)}\n\boxed{\bold{Q2}\ 2^(25)}$

Step-by-step explanation:

$\bold{Q1}\n\n(-2(3^2\cdot3^3)^2)/(3^(12)\cdot2^(-6))\qquad\text{use}\ a^n\cdot a^m=a^(n+m)\n\n=-(2(3^(2+3))^2)/(3^(12)\cdot2^(-6))=-(2(3^5)^2)/(3^(12)\cdot2^(-6))\qquad\text{use}\ (a^n)^m=a^(nm)\n\n=-(2\cdot3^(5\cdot2))/(3^(12)\cdot2^(-6))=-(2\cdot3^(10))/(3^(12)\cdot2^(-6))\qquad\text{use}\ (a^n)/(a^m)=a^(n-m)\n\n=-2^(1-(-6))\cdot3^(10-12)=-2^(7)\cdot3^(-2)\qquad\text{use}\ a^(-n)=(1)/(a^n)\n\n=-2^7\cdot(1)/(3^2)=-(2^7)/(3^2)=-(128)/(9)$

$\bold{Q2}\n\n(4^2)/(4^(-7))\cdot(2^4\cdot2^3)\cdot(3^(-2))^0\qquad\text{use}\ (a^n)/(a^m)=a^(n-m),\ a^n\cdot a^m=a^(n+m),\ a^0=1\n\n=4^(2-(-7))\cdot2^(4+3)\cdot1=4^(9)\cdot2^7=(2^2)^(9)\cdot2^7\qquad\text{use}\ (a^n)^m=a^(nm)\n\n=2^(2\cdot9)\cdot2^7=2^(18)\cdot2^7\qquad\text{use}\ a^n\cdot a^m=a^(n+m)\n\n=2^(18+7)=2^(25)$

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