a block of mass 5kg slides down an inclined plane that has an angle of 10 degrees if the inclined plane has no friction and the block starts at a height of 0.8m how much kinetic energy does the block have when it reaches the bottom? acceleration due to gravity is 9.8m/s2. someone help me how to solve this, physics conservation of energy

Answers

Answer 1
Answer:

The physics conservation of energy E = 39.2 joules.

To calculate the Physics conservation of energy.

Mass of the block, m = 5 kg

At the top, the block will have only potential energy which is given by :

P=mgh

At the bottom of the inclined plane, it will have only kinetic energy which is given by :

E=(1/2)mv2

Applying the conservation of energy as :

E=(1/2)mv2=mgh

E=5*9.8*0.8

E = 39.2 joules.

The physics conservation of energy E = 39.2 joules.

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Answer 2
Answer: In this case, the inclined plane is frictionless and therefore energy is perfectly conserved with no losses. The block originally starts off with some gravitational potential energy, which is then completely converted into kinetic energy. So the initial gravitational potential energy is equal to the final kinetic energy.

PE_(initial) =  KE_(final)
PE_(initial) =mgh=(5kg)(9.8m/ s^(2) )(0.8m)=39.2 joules
KE_(final)=39.2joules

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Answers

Answer:

θ = 19.47°

Explanation:

given,

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direction = ?

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Answers

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Answers

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Answer:

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Answers

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Answers

Answer:

X=dt

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hope it helps...