The missile's change in altitude from the starting point 290 feet below sea level to the final position of height 17800 feet is calculated by subtracting the initial position from the final position, resulting in a change of 18090 feet.
The subject of this question falls under the domain of Mathematics, specifically involving numerical operations. It pertains to the calculation of change in altitude. Here's your step-by-step explanation:
1. The missile's starting point is 290 feet below sea level. We represent below sea level as a negative number, so the starting altitude of the missile is -290 feet.
2. The missile then ascended to a height of 17800 feet, which is above sea level and hence positive.
3. To find the change, we subtract the initial position from the final position: 17800 - (-290) = 17800 + 290 = 18090 feet.
So, the change in altitude of the missile is 18090 feet.
#SPJ2
0.26 x 1/10 =0.026
a. 290 mod 26
b. 9^{-1} mod 26
c. -15 mod 26
The results of the modulo operations are: 290 mod 26 results in 2; 9^{-1} mod 26 is equivalent to 3; and -15 mod 26 equals 11.
To simplify each of the following with justifications:
#SPJ12
Answer:
this is c
Step-by-step explanation:
Luisianna