Contrary to what you might think, abusive relationships can actually begin happily with no problems at all. The answer is C).
B)5-20s
C) 20-4
D)40-50s
Answer:
Should be D the correct answer
Explanation:
Answer:
D
Explanation:
because the slope decreases
Answer:
nucliare fussion happens in the core of the sun
Explanation:
Celsius scale
Fahrenheit scale
Kelvin scale
93,000
930,000
9,300,00
Answer:
930,000
Explanation:
9.3 x 10^5
The power of 10 (5 in this question) gives the number of times the decimal point is to be moved to the right.
If there was a negative sign in front of the power, the number would have been an indication of how many times the decimal point is to be moved to the left.
Further to this
9.3 x 10^5 = 9.30000000 x 10^5
= 930000.000
= 930,000
Answer:
508Hz
Explanation:
A tuning fork with a frequency of 512 Hz is used to tune a violin. When played together, beats are heard with a frequency of 4 Hz. The string on the violin is tightened and when played again, the beats have a frequency of 2 Hz. The original frequency of the violin was ______.
When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - this phenomenon is beat production
frequency is the number of oscillation a wave makes in one seconds.
f1-f2=beats
therefore f1=512Hz
f2=?
beats=4Hz
512Hz-f2=4Hz
f2=512-4
f2=508Hz
the original frequency of the violin is 508Hz
The original frequency of the violin was 508 Hz. This is based on the principle of beats, where the beat frequency is the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
The original frequency of the violin string can be found using the principle of beats. The frequency of the beats is equal to the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
Initially, the beat frequency was heard as 4 Hz. This indicates that the original frequency of the violin was either 512 Hz + 4 Hz = 516 Hz, or 512 Hz - 4 Hz = 508 Hz. However, when the violin string was tightened, the beat frequency decreased to 2 Hz, which means the frequency of the note it was producing increased.
Therefore, the violin must have initially been producing a note with lower frequency (508 Hz), and even after tightening the string, the note it now produces (510 Hz) remains lower than that of the tuning fork.
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