Answer : Protein
Explanation : When the scientist isolated the water soluble compound from the spider venom it had elements such as carbon,nitrogen, hydrogen and oxygen in its chemical structure this gives an assumption of the compound being a protein. But, further confirmation was given when it was injected under the mice skin and which broke down the structural materials in the cell membrane, this is one of the property of protein. And he is going to find out about its toxicity to humans.
The compound from spider venom is likely an alkaloid, a class of compounds often involved in cell membrane disruption and known for their psychotropic and physiological effects on humans. It might have potential medicinal uses like other animal toxins currently under research.
The compound described in the question, which is derived from spider venom and contains nitrogen, carbon, hydrogen, and oxygen, is most likely a type of alkaloid. Alkaloids are naturally occurring chemical compounds containing mostly basic nitrogen atoms. They have a range of effects on living organisms but are often involved in cell membrane disruption. Examples include substances like morphine, codeine, and heroin, as well as various animal toxins currently under study for their medicinal potential. It's worth noting, that medicinal uses of animal toxins is not a new concept. Compounds similar to snake venom, for example, have found uses as antivirals and painkillers. Future research will reveal the exact mechanism and potential medicinal uses of this spider venom-derived compound.
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The theoretical yield : = 10.251 g
Given
Reaction
3H₂(g)+N₂(g)→2NH₃(g)
1.81 g H₂
10.2 g N₂
2.19 g NH₃
Required
The theoretical yield
Solution
Find limiting reactant :
H₂ : 1.81 g : 2 g/mol = 0.905 mol
N₂ : 10.2 g : 28 g/mol = 0.364 mol
mol : coefficient
H₂ = 0.905 : 3 = 0.302
N₂ = 0.364 : 1 = 0.364
H₂ as a limiting reactant(smaller ratio)
Moles NH₃ based on H₂, so mol NH₃ :
= 2/3 x mol H₂
= 2/3 x 0.905
=0.603
Mass NH₃ :
= mol x MW
=0.603 x 17 g/mol
= 10.251 g
The electron configuration for lithium . So, the correct answer is C.
The electron configuration of an element describes how electrons are distributed in its atomic orbitals. Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells (with the number of electrons they hold written in superscript) are placed in a sequence.
The atomic number of lithium is 3. So, the electronic configuration is as follows:-
So, the correct option is C.
Learn more about the electronic configuration here:-
Answer:
C
Explanation:
just took the test on edge
Answer;
-past temperatures
The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine past temperatures.
Explanation;
-O-16 will evaporate more readily than O-18 since it is lighter, therefore; during a warm period, the relative amount of O-18 will increase in the ocean waters since more of the O-16 is evaporating.
-Hence, looking at the ratio of O16 to O18 in the past can give clues about global temperatures.
Answer: A solid is something that can hold its own shape and is hard to compress (squash). However, ice is different from most solids because its molecules are less densely packed than in liquid water so ice takes up a little more space than the same amount of liquid water. This is why ice floats.
Explanation: Hope it works!!!!!
b. 50.00 mL
c. 75.00 mL
d. 100.00 mL
e. 25.00 mL
Answer:
We need 75 mL of 0.1 M NaOH ( Option C)
Explanation:
Step 1: Data given
Molarity of NaOH solution = 0.100 M
volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L
Step 2: The balanced equation
CH3COOH + NaOH → CH3COONa + H2O
Step 3: Calculate moles of CH3COOH
Moles CH3COOH = Molarity * volume
Moles CH3COOH = 0.150 M * 0.05 L
Moles CH3COOH = 0.0075 moles
Step 4: Calculate moles of NaOH
For 1 mol of CH3COOH we need 1 mol of NaOH
For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH
Step 5: Calculate volume of NaOH
volume = moles / molarity
volume = 0.0075 moles / 0.100 M
Volume = 0.075 L = 75 mL
We need 75 mL of 0.1 M NaOH
2) 2.01 mol N2O
Answer :
Part 1: 4.93 moles of contains 9.86 moles of oxygen atoms.
Part 2: 2.01 moles of contains 2.01 moles of oxygen atoms.
Explanation :
Part 1: 4.93 mol
In 1 mole of , there are 2 atoms of hydrogen and 2 atoms of oxygen.
As, 1 mole of contains 2 moles of oxygen atoms.
So, 4.93 moles of contains moles of oxygen atoms.
Thus, 4.93 moles of contains 9.86 moles of oxygen atoms.
Part 2: 2.01 mol
In 1 mole of , there are 2 atoms of nitrogen and 1 atom of oxygen.
As, 1 mole of contains 1 mole of oxygen atoms.
So, 2.01 moles of contains moles of oxygen atoms.
Thus, 2.01 moles of contains 2.01 moles of oxygen atoms.