Answer:
A dog needs 4/3 liters of water 2/5 of a day, Therefore
he'll need 4/3 liters for 5/2 day or
4/3 * 5/2 = 20/6 = 10/3 liters or 3 and 1/3 liters per day
Step-by-step explanation:
Answer:
The correct answers are
1) There must be at least 10 observed successes and 10 observed failures in the sample from population 1.
3) There must be at least 10 observed successes and 10 observed failures in the sample from population 2.
Step-by-step explanation:
Hello!
You have two variables of interest:
X₁: Number of that had to put off medical treatment due to cost during 2016.
n₁= 967 people surveyed
x₁= 184 answered "yes"
sample proportion p'₁= 184/967= 0.19
X₂: Number of that had to put off medical treatment due to cost during 2019.
n₂= 1015 people surveyed
x₂= 253 answered "yes"
p'₂= 253/1015= 0.25
The pooled sample proportion is
To study the population proportion you have to apply the Central Limit Theorem to approximate the distribution of the sample proportion to normal, the conditions for a valid approximation are:
Sample size n ≥ 30
n₁= 967
n₂= 1015
n*p'≥10 (each sample contains at least 10 successes)
n₁*p'₁= 967*0.19= 183.73
n₂*p'₂= 1015*0.25= 253.75
n*(1-p')≥10 (each sample contains at least 10 failures)
n₁*(1-p'₁)= 967*0.81= 783.27
n₂*(1-p'₂)= 1015*0.75= 761.25
The correct answers are
1) There must be at least 10 observed successes and 10 observed failures in the sample from population 1.
3) There must be at least 10 observed successes and 10 observed failures in the sample from population 2.
I hope it helps!
Answer:
v=3
Step-by-step explanation:
15v-9v=18
6v = 18
6 6
v = 3
Answer:
Step-by-step explanation:
There are 9 possible outcomes for (Bill, Ben)'s cards:
(4, 4) total 8; (4, 5) total 9; (4, 6) total 10;
(5, 4) total 9; (5, 5) total 10; (5, 6) total 11;
(6, 4) total 10; (6, 5) total 11; (6, 6) total 12.
Of these 9 outcomes, 4 have an odd total; 6 are less than 11.
P(odd) = 4/9
P(sum < 11) = 2/3