The required price of the paperback book and hardback book is $2.95 and $13.95 respectively.
Given that,
The cost of a paperback book is 11 dollars less than the cost of a hardback book. Recently one day of sales totaled $784.10. That day the bookstore sold 53 paperback books and 45 hardback book.
Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.
Here,
Let the price of paperback be x and price of hardback books be y,
According to the question,
x = y - 11 - - - (1)
53x + 45y = 784.10 - - - (2)
From equation 1
53 [y - 11] + 45y = 784.10
y = $13.95
Now,
y = 13.95 - 11
y = $2.95
Thus, the required price of the paperback book and hardback book is $2.95 and $13.95 respectively.
Learn more about simultaneous equations here:
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Answer:To determine the area of a regular hexagon, we need to use the formula:
Area = (3√3 * s^2) / 2
Where:
- s represents the length of one side of the hexagon.
In the given question, the side length of the regular hexagon is not provided. Therefore, we cannot calculate the exact area without that information.
However, if we assume the side length is 7.79 meters, we can substitute it into the formula to find the area:
Area = (3√3 * (7.79)^2) / 2
Area = (3√3 * 60.6641) / 2
Area ≈ 104.434 square meters (rounded to three decimal places).
Again, please note that this answer assumes the side length of the hexagon is 7.79 meters. If the actual side length is different, the area will also be different.
Step-by-step explanation:sorry for this guys meanness he did it to me to
-4
-2
0
4
Answer:
-4
Step-by-step explanation:
The number inside of the ( ) for a log must be greater than 0.
27 Pa
416 Pa
1728 Pa
The ideal gas law can be presented as:
PV = nRT
where
P - pressure of the gas,
V - volume of the gas,
n - amount of substance of gas,
R - gas constant,
T - temperature of the gas.
But, we do not need to know all of the equation members since the right side of the equation is not affected and will remain the same. It is enough the left side of the equation:
P₁V₁ = P₂V₂
It is given:
P₁ = 104 Pa
V₁ = 108 L
V₂.= 432 L
The unknown is P₂ = ?
P₁V₁ = P₂V₂.
104 Pa × 108 L = P₂ × 432 L
11,232 Pa L = P₂ × 432 L
P₂ = 11,232 Pa ÷ 432
P₂ = 26 Pa
Therefore, the new pressure will be 26 Pa.