MATHEMATICS HIGH SCHOOL

John's library has 3 hardcover books for every 8 paperbacks. If he has 121 books in his library, how many of them are paperbacks. Will mark brainliest if correct. Pls show work.

Answers

Answer 1

Answer:

Answer: 88

Step-by-step explanation:

1. Add 3 and 8 together

3 + 8 = 11

2. Divide 121 by 11

121/ 11 = 11

3. Multiply the amount of paperbacks in the stack of 11 books (8) by 11

11 x 8 = 88

88 Is your answer.

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What is the length of AC ? Round to the nearest tenth.10.5 m
12.3 m
18.3 m
21.4 m

Answers

The length of AC is equal to 10.5m

Data;

AC = ?
BC = 15m
Angle = 55 degrees

Trigonometric Ratio

To solve this problem, we have to apply trigonometric ratioSOHCAHTOA here;

Since we have the value of opposite side, angle and we are looking for the adjacent, we can use tangent of the angle to find AC
$tan\theta = (opposite)/(adjacent)$

Let's substitute the values and solve for AC

$tan 55 = (15)/(AC) \nAC = (`15)/(tan55) \nAC = 10.5m$

From the calculations above, the length of AC is equal to 10.5m

Learn more on trigonometric ratio here;

brainly.com/question/24349828

In this right triangle, side AC is adjacent to the reference angle we were given. That's our unknown. The other side is the side opposite the reference angle, so we need a trig ratio that relates the side adjacent to the side opposite which is tangent. Setting up our ratio we have this: $tan(55)= (15)/(x)$ and $x= (15)/(tan(55))$ . Do that on your calculator to find that side AC (x) = 10.5, first choice above.

Line KL has an equation of a line y = 4x + 5. Which of the following could be an equation for a line that is perpendicular to line AB? (6 points)y = 4x − 8

y = 1 over 4x − 8

y = −4x − 8

y = −1 over 4x − 8

Answers

To find a perpendicular slope (or line), the slope (in this case 4x) must be the opposite sign and its reciprocal, which is basically the fraction flipped upside down. Since 4 is technically 4/1, that fraction flipped is 1/4. And since you need to flip the sign too, instead of it being a positive number, it's negative. Your answer is -1/4x-8

y = -1 over 4x - 8 is the answer I think

THERE'S TOO MUCH CATFISHES ON THIS SITE

Answers

Answer:

what do you mean by that?

Step-by-step explanation:

For today’s lunch, a school cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn. 1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. Each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch. If a can of beans cost $2.00 and a can of corn cost $3.00, what is the maximum amount of money required to feed all of the students either beans or corn?A: $180

B: $195

C: $210

D: $225

Answers

Answer:

Option B.

Step-by-step explanation:

Let x be the number of cans of beans and y be the number of cans of corn.

Cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn.

$x\leq 60$

$y\leq 45$

1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. Each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch.

$5x+6y\leq 420$

Can of beans cost $2.00 and a can of corn cost $3.00.

Objective function, Z=2x+3y

The required linear programming problem is

Objective function, Z=2x+3y

Subject to the constraints

$x\leq 60$

$y\leq 45$

$5x+6y\leq 420$

$x\geq 0, y\geq 0$ (Only 1st quadrant)

Draw the graph of these constraints as shown below.

The verities of common shaded region are (0,45), (30,45), (60,20), (60,0), (0,0).

Points Z=2x+3y

(0,0) 0

(0,45) 135

(30,45) 195

(60,20) 180

(60,0) 120

The maximum amount of money required to feed all of the students either beans or corn is $195.

Number of cans of beans = 30

Number of cans of corn = 45

Therefore, the correct option is B.

I would go with B, one hundred ninety five dollars. Hope that this would help you..

A game spinner has regions that are numbered 1 through 8. if the spinner is used twice, what is the probability that the first number is a 3 and the second is a 6? a. 116 b. 164 c. 964 d. 23