A car with a cost of $25,000 is decreasing in value at a rate of 10% each year. The function g(t)= 25,000(0.9)^t gives the value of the car after t years. When will the value of the car be about $12,000? A) after 7 years B) after 9 years C) after 13 years Could you also explain how to do it?

Answers

Answer 1

Answer: 12,000 = 25,000 $(0.9)^(t)$
Divide both sides by 25,000 → 0.48 = $(0.9)^(t)$
Convert to log form → $log_(0.9)$ 0.48 = t
Use the change of base formula → $(log 0.48)/(log 0.9)$ = t
Plug into the calculator → 6.966 = t

Answer: A

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Answers

I am more than happy to help but i need you to tell me the dropbox options please :)

If they are 1,2 and 3 in the dropbox then:

1) would be 1

2) would be 3

3) would be 2

Answer:

they're all aligned with they're answers actually

num 1 would go with the first one, the num 2 would go with the second one, and num 3 one would go to the third one

~batmans wife dun dun dun...aka ~serenitybella

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Answers

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Plz answer rn nmmmm ASAP!!

Answers

Answer:

Step-by-step explanation:

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