PLEASE ANSWER + BRAINLIEST!!What is the point of intersection when the system of equations below is graphed on the coordinate plane?

A. (1, –3)

B. (–1, 3)

C. (1, 3)

D. (–1, –3)

Answers

Answer 1

Answer: The correct answer is B. (-1, 3)

Hope this helps :)

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Tomas bought a book that cost $18. it was on sale for 84% of its original price. how much did tomas pay

Answers

Answer: 15.12

Step-by-step explanation:

84% of 18

=84/ 100 × 18

=84× 18 / 100

=1512/100

=15.12

The original price is $15.12

You said so yourself, Tomas paid $18.
The original price of the book was about $21.43.

5 4/8 = ? I really need help

Answers

if you mean in decimal form, it will be 5.5

How to find the perimeter and the area of a rectangle on a coordinate plane using the distance formula? : A(3,8) B(5,4) C(-4,-1) D(-6,3) Round to the nearest tenth if necessary.

Answers

I used some site to plot the points.

First, let's recall the formulas for Perimeter and Area of a Rectangle.
Perimeter = 2(l+w)
Area = l×w
Also, the distance formula is
D = $\sqrt{( x_(2)-x_(1))^2+{(y_(2)-y_(1))^2}$

Now, we need to determine l and w.
So, the length is the distance of AD or BC
and the width is the distance of DC or AB
(I'll just use the sides that I've labelled for ease)

So first to determine the length, we need to calculate the distance of AD
Points are A(3,8) and D(-6,3)
$x_(1) =3, x_(2) =8, y_(1) =6, y_(2) =-3$
$D_(AD)= \sqrt{( 6-3)^2+{(-3-8)^2}$
$D_(AD)= √((3)^2+(-11)^2)$
$D_(AD)= √(9+121)$
$D_(AD)= √(130) ≈ 11.40$
So the length of the rectangle is 11.40 units.

Now, the width!
So first to determine the width, we need to calculate the distance of DC
Points are D(-6,3) and C(-4,-1)
$x_(1) =6, x_(2) =-4, y_(1) =-3, y_(2) =-1$
$D_(DC)= \sqrt{(-4-6)^2+{(-1- -3)^2}$
$<span>D_(DC)= \sqrt{(-4-6)^2+{(-1+3)^2}$
$D_(DC)= √((-10)^2+(2)^2)$
$D_(AD)= √(100+4)$
$D_(AD)= √(104) ≈ 10.20$
So the width of the rectangle is ≈10.20 units.

Let's now solve for Perimeter and Area using
l = 11.40
w = 10.20

Perimeter = 2(l+w)
Perimter = 2(11.40+10.20)
Perimter = 2(21.60)
Perimter = 43.2 units

Area = l×w
Area = (11.40)(10.20)
Area = 116.28
Area = 116.3 units² (rounding)

In conclusion, given points A(3,8) B(5,4) C(-4,-1) D(-6,3), the Perimeter is 43.2 units and the Area is ≈116.3 units² using the distance formula.

V = u + 10t
Work out the value of v when
u = 10 and t = 7