Answer:
The area function is
.
The domain and range of A is and .
Step-by-step explanation:
The given length of fencing is .
Let the length and width of each pen be and respectively as shown in the figure.
As there are 3 pens, so, the total area,
From the figure the total length of fencing is .
Here, for a significant area for the animals, as well as as and are the sides of ben.
From the given value:
Now, from equation (i)
This is the required area function in the terms of variable .
For the domain of area function, from equation (ii)
[as y>0]
So, the domain of area function is .
For the range of area function:
As or , then [from equation (i)]
Now, differentiate the area function with respect to .
Equate to zero to get the extremum point.
Check this point by double differentiation
As, , so, point is corresponding to maxima.
Put this value back to equation (iii) to get the maximum value of area function. We have
Hence, the range of area function is .
The area of each pen can be expressed as A(x) = x * (90 - 2x) / 3. The domain of this function is 0 < x < 45, and the range is 0 < A(x) < 300
In this problem, since Pam has to divide the petting zoo into three parts, we can consider the width of each pet pen to be x and the total length of the three pens to be (90 - 2x)/3, given that the total fence is 90m and we have two fences that are x meters long separating the pens. So, the area, A of each pen can be expressed as a function of x: A(x) = x * (90 - 2x) / 3. The domain of this function, or the possible values of x, would be all the values that make the area positive, which are 0 < x < 45. For the range of the function, we analyze the quadratic function which will have a maximum value at x = 15, as the area will be largest when the space is divided evenly, so the maximum area is A(15)= 15 * (60) / 3 = 300. Therefore, the range of the function is 0 < A(x) < 300.
#SPJ11
Answer with explanation:
A set of numbers that is triplet is said to form the sides of a right triangle, if it satisfies Pythagorean Theorem,which states that
Square of longest side is equal to sum of Squares of other two sides.
1.First triplet=4,4,4
As, 4²≠4²+4²
Hence it does not form Pythagorean triplet.
2. Second triplet=4, 6.93, 8
Largest side length =8
8²=64
Sum of squares of two smaller sides =(6.93)²+4²
=48.0249+16
=64.0249
=64
3. Third triplet=11.2, 16.2, 19.2
Largest side length =19.2
(19.2)²=368.64
Sum of squares of two smaller sides =(11.2)²+(16.2)²
=125.44+262.44
=387.88
=388(approx)
Option B ⇒4,6.93, 8
□44
□19
□17
□11
Answer:
11
Step-by-step explanation:
3 (4 - n) + 8
When n = 3:
3 (4 - 3) + 8
3 (1) + 8
3 + 8
11
Answer:
11
Step-by-step explanation:
B) two triangles are similar if any sides of one triangle are congruent to any two sides of another triangles
C) two triangles are similar if corresponding sides form a proportion
D) two triangles are congruent if corresponding sides form a proportion
0.4, 0.505, 0.449, 0.48 or 0.53?
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Let's solve the problem given to us today! The problem is the following:
We need to solve for x.
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First, subtract 11 from both sides:
Simplify:
Divide both sides by -8:
Simplify:
Therefore, x = 0.
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