A block slides down a rough ramp with a 30-degree incline as shown.
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Final answer:
The question involves a block sliding down a 30-degree incline, where the forces of gravity, normal force, and friction are in effect. The acceleration of the block can be determined by taking into account all the forces acting on it. This is a topic in Physics, typically studied at the high school level.
Explanation:
In the described scenario, a block is sliding down a rough ramp inclined at 30 degrees. This topic falls under the area of Physics, specifically in the study of friction and forces. The forces at play in this situation are gravity, normal force, and frictional force. When a block slides down an inclined plane, the force of gravity is divided into two components. The component parallel to the ramp, mg sin θ, acts downwards and is opposed by the force of friction.
The frictional force is determined by multiplying the normal force by the coefficient of friction (μ). This could be represented as F = μN, where F is the frictional slide and N is the normal force. The block's acceleration depends on the net force acting on it, considering all the forces at play.
In this particular situation, where there's a known coefficient of friction of 0.20 and given gravitational and normal forces are 40 N, you can use these values, along with the angle of the ramp, to find the acceleration of the block using formulae from physics.
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Final answer:
A block sliding down a rough incline experiences forces from gravity, friction, and normal force. Friction opposes the motion, reducing the acceleration the block would have on a frictionless slope. The acceleration can be calculated from the incline angle and friction coefficient.
Explanation:
The question deals with the physics of a block sliding down a rough, incline plane. When a block is sliding down an inclined plane, there are several forces at play. The gravitational force pulls the block downwards, the normal force counters this directly perpendicular to the slope, and friction acts to oppose the motion of the block. The coefficient of friction between the block and the incline plays a crucial role in the block's acceleration down the incline.
The acceleration of the block can be calculated using the formula a = g sin θ, where g is acceleration due to gravity and θ is the incline angle. However, this applies when there's negligible friction. If friction is involved, it reduces the acceleration from this value. The acceleration on an incline where there is friction can be calculated with the equation ax = g sin θ - μk g cos θ, where μk is the coefficient of kinetic friction.
Using the equation above, you can calculate acceleration if you are given the friction coefficient and the incline's angle. However, if you're given the acceleration and either the incline angle or friction coefficient, you can rearrange the equation to calculate the missing variable, helping you gain more understanding about the impacts of the slope and friction.
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Related Questions
Which situations contain unbalanced forces? Check all that apply.
The cheetah, which is the fastest land mammal, can accelerate from 0.0 mi/hr to 70.0 mi/hr in 3.0 seconds. What is the acceleration of the cheetah? Give your answer in units of mph/sec.
What object in the solar system is always one foci
A constellation is _______ that forms a pattern resembling animals, mythological characters, or objects.A. a group of meteorsB. a group of starsC. an entire galaxyD. one single planet
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There are a group of scientists who worked together to developed the Higgs Boson ttheory such as Jon Botterworth , but the particle finally named after Peter Higgs out of respect since he's the one who 1st explicitly predict it
Answer:
He was among the first to propose its existence.
Explanation:
In July of 2012, physicists found it. This last boson was named the Higgs, after the British physicist Peter Higgs, who was among the first to propose its existence.
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rearrange: Vf=at
solve: Vf= 4.0m/s squared x 6s
Vf = 24 m/s --> sigdigs
Vf = 2.4 x 10^1 m/s
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Answer:
option A
Explanation:
given,
momentum of blue car in west direction = Pa = 2 kg.m/s
momentum of red cart in east direction = Pb = 3 kg.m/s
total momentum of the two cart = ?
Pa = 2 Kg.m/s
Pb = -3 kg.m/s
Total momentum
P = Pa + Pb
P = 2 - 3
P = - 1 kg.m/s
hence, the total momentum of the two carts after the collision is 1.0 kg•m/s
The correct answer is option A
conductor
transformer
electromagnet
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Icebergs are composed of freshwater and freshwater is more dense then salt water.
Icebergs are colder then the ocean water and cold water is less dense then warm water.
Icebergs are colder then the ocean water and cold water is more dense then salt water.
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B. The farthest point in the Moon's orbit to Earth
C. The closest point in Earth's orbit of the Sun
D. The Sun's orbit that is closest to the Moon
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Answer:
A. The closest point in the Moon's orbit to Earth
Explanation:
The perigee is defined as the closest point in the orbit of an object (such as a satellite) from the centre of the Earth. In this case, the Earth's satellite is the Moon, so the perigee is defined as the closest point in the Moon's orbit to Earth. so option A is the correct one.
Let's see instead the names of the other options:
B. The farthest point in the Moon's orbit to Earth --> this point is called apogee
C. The closest point in Earth's orbit of the Sun --> this point is called perihelion
D. The Sun's orbit that is closest to the Moon --> this point has no specific name
Hope I helped:P