Answer:
Motor neurons stimulate muscle cells so that Dina can move to put on her coat.
Explanation:
O Broca's area
Wernicke's area
Motor cortex
Cerebellum
Wernicke's area is most likely to have been damaged in Fatima's case.
The area of Fatima's brain most likely to have been damaged is Wernicke's area. Wernicke's area is responsible for the comprehension and production of spoken and written language. Damage to this area can result in difficulties understanding spoken language, as in Fatima's case. This area is located in the left hemisphere of the brain, near the auditory cortex.
Answer:
The reduced form of cytochrome c more likely to give up its electron to oxidized cytochrome a having a higher reduction potential.
Explanation:
Electrons from NADH and FADH2 flow spontaneously from one electron carrier of the electron transport chain to the other. This occurs since the proteins of the ETC are present in the order of increasing reduction potential. The reduced cytochrome b has lower reduction potential than cytochrome c1 which in turn has a lower reduction potential than the cytochrome c.
Cytochrome c is a soluble protein and its single heme accepts an electron from cytochrome b of the Complex III. Now, cytochrome c moves to complex IV which has higher reduction potential and donates the electron to cytochrome a which in turn passes the electrons to O2 via cytochrome a3.
Answer:
d
IDK if there is a explanation but if there is i can do so
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Cry Shape HeartyAnswer:Cry Shape Hearty
Cry Shape HeartyCry Shape Hearty
Cry Shape HeartyExplanation:Cry Shape Hearty
Cry Shape HeartyCry Shape Hearty
The best way of solving this is to draw a Punnett square.
You know the F0 had one parent with singed bristles (s), and normal wings (L), and the other parent is normal bristles (S) with vestigial wings (l).
If you do the cross ssLL x SSll you'll find 100% of the offspring is F1: SsLl, this means, all of them show the dominant traits: normal wings and normal bristles.
If you cross two parents from F1 to have F2, you'll find:
SsLl x SsLl = SSLL + SslL + sSlL+ ssll = 25% SSLL,all dominant traits. 50% SsLl is a recessive trait carrier but shows dominant traits. 25% ssll this one has all recessive alleles, which means, it will show vestigial wings and signed bristles.
Answer:
The resistance allele is recessive
Explanation:
According to Darwin's pea experiment, the recessive trait appeared after a few generations.
Here in this case too the resistant individuals appeared after the first generation. This also implies that the offspring of first generation must be carrier of this recessive trait.
Let the susceptible domesticated strain trait be represented by "S"
and the recessive resistant wild strain trait be represented by "s"
Then,
F1 generation
SS * ss
Ss, Ss, Ss, Ss ------ All are heterozygous susceptible individuals
F2 generation
Ss * Ss
SS, Ss, Ss, ss
ss shows reappearance of resistant wild trait.
Hence, the resistance allele is recessive.