What is the value of y

Answers

Answer 1

Answer: i think its c
hope this helps

Answer 2

Answer: two equal angles, so it's isosceles triangle
sum of triangle = 180
so
2y + 54 = 180
2y = 126
y = 63

answer
b) 63

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Which could be the function graphed below?

Answers

I believe the answer is the first choice. If I’m correct, the numbers outside of the square root are the y intercept, the graph is clearly starting in the negatives, it could be -2 (it being the y intercept). I hope this is right, my apologies if it isn’t.

What is the first 12 numbers in pi?

Answers

3.14159265359 is the first 12 numbers in pi!
your welcome!

The first 12 digits of pi are:
3.14193265359

what are the coordinates of the vertex of the table is it a minimum or maximum A. (-4,1) B(-2,-3) minimum C. (-2,-3) maximum D. (1,0)

Answers

minimum C. (-2,-3) cameron mcdaniel

Answer:

(-2, -3); minimum is correct.

Step-by-step explanation:

The image shows a geometric representation of the function f(x) = x2 – 2x – 6 written in standard form.What is this function written in vertex form?

f(x) = (x –1)2 – 7

f(x) = (x +1)2 – 7

f(x) = (x –1)2 – 5

f(x) = (x +1)2 – 5

Answers

we know that

To find the equation in vertex form, we need to factor the function

$f(x) = x^(2) - 2x - 6$

Complete the square. Remember to balance the equation

$f(x) = x^(2) - 2x +1-1- 6$

$f(x) = x^(2) - 2x +1-7$

Rewrite as perfect squares

$f(x) = (x-1)^(2) -7$

in this problem

the vertex is the point $(1,-7)$

therefore

the answer is

The function written in vertex form is equal to $f(x) = (x-1)^(2) -7$

Answer:

First one

Step-by-step explanation:

0.6x-0.3y=-1.5
0.04x-0.02y=-0.1

Answers

6x - 3y = -15; /* 2 => 12x - 6y = -30;
4x - 2y = -10; /*(-3) => -12x + 6y = 30
____________
=> 0 = 0 True, for every x and every y real numbers;

the solution is {(x, 2x + 5) / x∈R };

Maximum or Minimum. Domain and range of
y=x^2-4x+4

Answers

$y=x^2-4x+4\n\na=1;\ b=-4;\ c=4\n\na > 0\ then\ minimum:\n\n(-b)/(2a)=(-(-4))/(2\cdot1)=(4)/(2)=2\n\ny_(min)=2^2-4\cdot2+4=4-8+4=0\n\n\ndomain:x\in\mathbb{R}\n\n\nrange:y\in\left<0;\ \infty\right)$

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