What is the temperature 32 degrees Fahrenheit in degrees Celsius?a. 20 degrees Celsius
b. 0 degrees Celsius
c. 10 degrees Celsius
d. 10 degrees Celsius

Answers

Answer 1

Answer: Using    (F - 32)/9 = C/5
Where F is Fahrenheit, C = Celsius.

Let F = 32, (32 - 32)/9 = C/5
   0/9 = C/5
      0 = C/5, therefore C = 0*5 = 0

32°F = 0°C

Answer 2

Answer:

Answer:so that means the answer 32°F = 0°C

Explanation:

Using (F - 32)/9 = C/5

Where F is Fahrenheit, C = Celsius.

Let F = 32, (32 - 32)/9 = C/5

0/9 = C/5

0 = C/5, therefore C = 0*5 = 0

32°F = 0°C

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What is the example of a sport related activity

Answers

sports are games so lets do process of elimination
A.) weight lifting (exercise)
B.) Soccer (sport)
C.) jump rope (exercise)
D.) Running a race (exercise) but questionable

i would say B.) soccer

The correct answer is B. Soccer
Hope this helps you and have a good night! :3

Who was the 1st to use film in intraoral radiography?

Answers

The first dental x-ray film was used by Dr. Frank Vanwoert.

a balloon is ascending at 3.0 m/s at a height of 20.0 m above ground when a package is released. the time taken, in the absence of air resistance, for the package to reach the ground is:

Answers

Answer:

Approximately $2.35\; {\rm s}$ , assuming that $g = 9.81\; {\rm m\cdot s^(-2)}$ .

Explanation:

Under the assumptions, the package would start with an initial upward velocity of $u = 3.0\; {\rm m\cdot s^(-1)}$ and accelerate downward at a constant $a = (-g) = (-9.81)\; {\rm m\cdot s^(-2)}$ (negative because acceleration points downward.)

Right before landing, the package would be $20.0\; {\rm m}$ below where it was released. Hence, the displacement of the package at that moment would be $x = (-20.0)\; {\rm m}$ (negative since this position is below the initial position.)

The duration of the motion can be found in the following steps:

Apply the SUVAT equation $v^(2) - u^(2) = 2\, a\, x$ to find velocity $v$ right before landing.
Divide the change in velocity $(v - u)$ by acceleration to find the duration of the motion.

Rearrange the SUVAT equation $v^(2) - u^(2) = 2\, a\, x$ to find $v$ , the velocity of the package right before reaching the ground. Notice that because the package would be travelling downward, the value of $v\!$ should be negative.

$\begin{aligned} v &= -\sqrt{u^(2) + 2\, a\, x} \n &= -\sqrt{(3.0)^(2) + 2\, (-9.81)\, (-20.0)}\; {\rm m} \n &\approx (-20.035)\; {\rm m}\end{aligned}$ .

Subtract the initial velocity from the new value to find the change in velocity. Divide this change in velocity by acceleration (rate of change in velocity) to find the duration of the motion:

$\begin{aligned}t &= (v - u)/(a) \n &\approx ((-20.035) - (3.0))/((-9.81))\; {\rm s} \n &\approx 2.35\; {\rm s}\end{aligned}$ .

50 cm to mA flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from 2.0 T to 6.0 T in 2.0 s. If the coil has a total resistance of 0.40 Ω, what is the magnitude of the induced current?

Answers

Answer:

0.025 A

Explanation:

A = 50 cm^2 = 50 x 10^-4 m^2

B2 = 6 T, B1 = 2 T

db = 6 - 2 = 4 T

dt = 2 s

R = 0.4 ohm

Let i be the magnitude of induced current and e be the induced emf.

According to the Faraday's law of electromagnetic induction

e = dФ / dt

e = A dB / dt

e = 50 x 10^-4 x 4 / 2 = 0.01 V

i = e / R = 0.01 / 0.4 = 0.025 A

Which statement best describes how light waves travel in a uniform medium. A. in straight lines. . B. in extending circles. . C. in bent lines. . D. in shrinking ripples

Answers

Light waves travel in straight lines when they are travelling in a uniform medium. This is because the waves are travelling at the same speed.

The answer is a. Straight lines

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