Assume that you have a mass of 50.0kg and earth has a mass of 5.97x10kg.The radius of earth is 6.38x10m.What is the force of gravitational attraction between you and the earth

Answers

Answer 1

Answer: The formula for force of attraction between any two bodies in the universe
F = GMm / r^2. (Newton's Universal law of Gravitation).

G = Universal gravitational constant, G = 6.67 * 10 ^ -11 Nm^2 / kg^2.
M = Mass of first object. = 5.97 x 10^24 kg.
m = mass of second object = 50 kg.
r = distance apart, between centers = in this case it is the radius of the earth
= 6.38 x 10^6 m.
( Sorry I could not assume with the values you gave).
(Actually the force of attraction between an object on the Earth and the Earth is the weight of the object our answer should be around 500N which is from mg = 50 *10 = 500)

So F = ((6.67 * 10 ^ -11)*(5.97 x 10^24)*(50)) / (6.38 x 10^6)^2.
Punch it all up in your calculator.
F = 489. 135 N.

Remember we said it would be around 500.
So that's our answer.
F = 489. 135 N. Hurray!!

Answer 2

Answer:

Final answer:

The force of gravitational attraction between you (of mass 50kg) and the Earth (of mass 5.97x10^24 kg) can be calculated using Newton's Universal Law of Gravitation. Substituting the respective values in the formula, the calculated force is approximately 490.5 N.

Explanation:

The force of gravitational attraction between you and the earth can be calculated using Newton's Universal Law of Gravitation. This law states that the force (F) between two masses (m1 and m2) separated by a distance (r) is given by the formula F = G*(m1*m2/r^2), where G is the gravitational constant and is approximately 6.67x10^-11 N*(m^2/kg^2).

In this case, your mass (m1) is 50 kg, Earth's mass (m2) is 5.97x10^24 kg and the radius of Earth (r) is 6.38x10^6 m. Substituting these values into the formula, we can find the force of gravitational attraction between you and the Earth.

F = (6.67x10^-11 N*(m^2/kg^2)) * ((50 kg) * (5.97x10^24 kg)) / (6.38x10^6 m)^2. After calculating the above equation, you find that F ≈ 490.5 N.

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A person can jump a maximum horizontal distance (by using a 45◦ projectile angle) of 5 m on Earth. The acceleration of gravity is 9.8 m/s 2 . What would be his maximum range on the Moon, where the free-fall acceleration is g 6 ? Answer in units of m

Answers

Answer:30 m

Explanation:

Given

Maximum Horizontal distance is 5 m on earth

launching angle $=45^(\circ)$

Acceleration due to gravity on earth is $9.8 m/s^2$

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A car travels at a steady speed of 10 m/s. What distance is covered in a minute?

Answers

Answer:

600

Explanation:

10*60=600

You multiply it by 60 because it is saying that it travels 1 mile per second and there are 60 seconds in one minute.

What is a likely consequence of preventing prescribed burns to forest ecosystems?

Answers

The forest ecosystem will regain back its natural ecology compared to burning of the forest and other illegal activities done to the forest. And also, some of the animals living in that forest will live and those that are endangered will not be threatened.

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Answers

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A spherical raindrop 2.7 mm in diameter falls through a vertical distance of 3950 m. take the cross-sectional area of a raindrop = πr2, drag coefficient = 0.45, density of water to be 1000 kg/m3, and density of air to be 1.2 kg/m3. (a) calculate the speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag.

Answers

Final answer:

The speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag is calculated by firstly finding the time it takes for the raindrop to fall this distance using equations of motion, and then using this time in the equation for final velocity. The calculated speed is approximately 2785.30 m/s.

Explanation:

To calculate the speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag, we must recall the equations of motion. The relevant equation here is Final velocity (v) = Initial velocity (u) + Acceleration (gravity, g) * time (t). However, since initial velocity (u) is 0 (when the drop starts falling, it's stationary), the equation simplifies to Final velocity (v) = g * t.

In free fall, a body accelerates under gravity (approximated as 9.81 m/s^2). In terms of time, difficulties arise because we don't know exactly when the raindrop will hit the ground. We can, however, calculate the time it would take for the raindrop to fall 3950 m by rearranging the equation distance (s) = ut + 0.5 * g * t^2 to solve for time. Removing (u), for the reasons explained earlier, we have the equation s = 0.5 * g * t^2. Solving this for time gives t = sqrt(s / (0.5 * g)). Substituting the given fall distance for s we get t = sqrt(3950 / (0.5 * 9.81)) or approximately 284.10 seconds.

Finally, we use this calculated time in our simplified velocity equation which gives v = g * t or 9.81 * 284.10, which equals approximately 2785.30 m/s.

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Which of the following can occur by conduction?a. transfer of heat from the sun
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c. transfer of heat through space
d. transfer of heat through a liquid

Answers

d. transfer of heat through liquid

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