PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELP!! WILL GET BRAINIEST IF YOU SHOW WORK 1. Simplify the radical


2. Simplify the radical


3. Simplify the radical


4. Simplify the radical
PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELP!! WILL GET BRAINIEST IF YOU SHOW WORK 1. - 4

Answers

Answer 1
Answer:

The simplification of the radical is c/3

What are radicals in math?

Radicals in math refer to expressions containing square roots or higher-order roots.

Represented by the radical symbol (√), they involve finding the root of a number. For example, √9 equals 3, as 3 * 3 equals 9.

Simplifying the surd;

√3c²)/√27

= √3 × √c²)/√9 × √3

= √3c/3√3

= c/3

Therefore the simplification of √3c²)/√27 is c/3.

learn more about radicals from

brainly.com/question/738531

#SPJ3

Answer 2
Answer: the root of 27 is 3root3.

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Answers

See, I think the new weight would be:
W1 = m(g + a) = mg + ma = W + ma = W + (W/g)a
about 85 pounds I think

How much is 1/9 of 3/8 (in lowest terms)?

Answers


We are asked to evaluate 1/9 of 3/8. This means we have to multiply 1/9 and 3/8. The product of the two factors is 3/ 72. Seeing the two factors on the other hand, we can cancel out 3. Hence the final answer to this problem in lowest terms becomes 1/24. 

X^3+13x^2+32x+20
please help me factorizing above equation

Answers

x^3+13x^2+32x+20=x^3+x^2+12x^2+ 12x+20x+20 =\n\n=x^2(x+1)+12x(x + 1 )+20(x+1 )=(x+1)(x^2+12x+20)=\n\n=(x+1)[(x^2+10x+2x+20)]=(x+1)[x(x +10)+2(x+10))]=\n\n=(x+1) (x +2) (x+10)


What is the place value of 4 7835.04​

Answers

Place value of 4 is 4/100

Which products are negative?Choose all answers that are correct.







A.

-1 1/4 · (-2 3/4) · (-3)






B.

1/2 · (-1/4) · (1/8)








C.

8 • (–1.1) • 5






D.

–3.1 • (–4.2) • (–6) • (–1.5)

Answers

A,B,and C because in when multiplying or dividing, + and - will be negative and if they are + and + or,  - and - then the answer will be positive.
all of them accept for d

I will make u the BRAINLIEST pls answer my question and explain!!!

Answers

The azalea is located at point (4, -4). You have already plotted the hydrangea at (4, 6). If you count up the number of squares from the hydrangea to the azalea plant, you will get a distance of 10. 

Since the problem tells you the length of each square is 1 ft, then you know that the distance between the two plants is 10 squares * 1 ft/square = 10ft. 
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