Answer:
2 successes = 80/243
0 successes = 32/243
at least 3 successes = 51/243
Step-by-step explanation:
Lets suppose we had the following sequence of 5 throws:-
2 or 3, 2 or 3 , then NOT 2 or 3 on last 3 throws
Probability of this is
1/3 * 1/3 * 2/3 * 2/3 * 2/3 = 8/243
There are (5*4) / 2 = 10 ways of having this result ( that is the number of combinations of 2 from 5 = 5C2 ).
So Prob(2 successes) = (8/243) * 10 = 80/243
Prob ( No successes) = (2/3)^5 = 32/243
Probability of 3 successes = 1/3 * 1/3 * 1/3 * 2/3 * 2/3 * 5C3
4/243 * 10 = 40 / 243
Probability of 4 successes = (1/3)^4 * 2/3 * 5C4
= 10/243
Probability of 5 success = (1/3)^5 = 1 / 243
Prob(at least 3 successes) = 51/243
Answer:
2 successes = 80/243
0 successes = 32/243
at least 3 successes = 51/243
Step-by-step explanation:
Lets suppose we had the following sequence of 5 throws:-
2 or 3, 2 or 3 , then NOT 2 or 3 on last 3 throws
Probability of this is
1/3 * 1/3 * 2/3 * 2/3 * 2/3 = 8/243
There are (5*4) / 2 = 10 ways of having this result ( that is the number of combinations of 2 from 5 = 5C2 ).
So Prob(2 successes) = (8/243) * 10 = 80/243
Prob ( No successes) = (2/3)^5 = 32/243
Probability of 3 successes = 1/3 * 1/3 * 1/3 * 2/3 * 2/3 * 5C3
4/243 * 10 = 40 / 243
Probability of 4 successes = (1/3)^4 * 2/3 * 5C4
= 10/243
Probability of 5 success = (1/3)^5 = 1 / 243
Prob(at least 3 successes) = 51/243
There is an infinite amount of rational numbers between -10 and 10.
A rational number is ant number that can be expressed in simple terms, this includes decimals.
Answer-1
Step-by-step explanation:
Answer: Well you see, I'm not gonna give u the answer kid. The explanation will help you more
Step-by-step explanation: If a line is perpendicular, then take the negative reciprocal of the slope. After that, use the point slope formula to write the equation
Answer:
y-10=-1/5(x-5)
Step-by-step explanation:
y-y1=m(x-x1)
m=slope
Answer if you look at the Shaded part you can tell that your using those parts and if you look at the blank part you're not using those parts hope this helps