Two road crews, working together, repaired 1 mile of road in 4 hours. working separately, one of the crews takes about 6 hours to repair a similar road. how much time would the other crew, working alone, need to repair a similar road?

Answers

Answer 1
Answer: see the attached photo

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Write a system of linear equations that has (-4, 8) as the solution. Once you have made your system of equations, solve it algebraically to show that you do indeed get the solution (-4, 8).
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And entryway floor is square with an area of 81 feet^2 which side length of a square rug would fit in the entryway with a border of 1 foot of floor around each edge? O 11 ft O 9ft O 8ft O7ft

Answers

Answer:

D.) 7 ft

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I think it’s A sorry if I’m wrong

Consider the function f(x) = 4x2 + 5. Find the value of f(x) when x = 2 and select the correct answer below.

Answers

Simply plug two in for x :)
f(2) = 4(2) × 2 + 5
f(2)=8 × 2 + 5
f(2)=16 + 5
f(2)=21
There's your answer :) (I just assumed that 2 was being multiplied when you said 4x2)

its supposed to be 4x^2.

What is 2n + -3 + 7 + 9

Answers

2n + -3 + 7 + 9
Answer : 2n+13

Answer:

2+ 13

Step-by-step explanation:

2n - 3 + 7 + 9

2n + 13

So if 2 people were working a job that paid 7.50 an hour, and worked 42 hours a week, how much money would they make together in a year?

Answers

They would make 32,760 together in a year. One person would make 7.50 a hour times 42 hours, which would be 315 a week. You would times that by 52 weeks in a year and get 16,380 for one person per year. Multiply 16,380 by two people and you would find that they make 33,760 a year.

What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?

Answers

sum is
S_(n)=(a_(1)(1-r^(n)))/(1-r)

r=common ratio
a1=first term
it looks like 2^0=1 is the first term aka a1
it goes to the 9th term (2^9)

sub
S_(9)=(1(1-(2)^(9)))/(1-2)
S_(9)=(1-512)/(-1)
S_(9)=(-511)/(-1)
S_(9)=511

so this one you don't multiply the base by the exponent. in this case its 2 times two how ever many time the exponent says.
2^0= 2
2^1= 2
2^2=4
2^3= 8
2^4=16
2^5=32
2^6=64
2^7=128
2^8=256
2^9=512
 So then you add all them up 
2+2+4+8+16+32+64+128+256+512= 1024

so there is your answer 1024


Find the y-intercept for the graph of the quadratic function. y + 4 = (x + 2)2 A. (0, 4) B. (0, 0) C. (4, 0) D. (0, -4

Answers

For y-intercept, x = 0.
y + 4 = (0 + 2)^2
y + 4 = 2^2
y + 4 = 4
y = 4 - 4 = 0

y-intercept is (0, 0)