Answer:
1/3025
Step-by-step explanation:
Prob. of getting a 9 is 1/55; likewise for 41. multiply the 2 probs. together. (1/55)^2=1/3025≈0.00033057851
The probability of drawing ball number 9 first and then drawing ball number 41 from a container of balls numbered 1 to 55, with replacement is 1/3025.
The question pertains to the field of probability in Mathematics. It is asking for the probability of first drawing ball number 9 and then drawing ball number 41 from a container that contains balls numbered from 1 to 55. Since the ball is replaced after the first draw, the total number of possibilities remains the same for both draws. Therefore, the individual probability of drawing either one of those balls at a certain draw is 1/55.
Given that these are independent events, we multiply the probabilities. Hence, the probability of drawing ball number 9 first and then drawing ball number 41 is: P(9 and 41) = P(9) x P(41) = (1/55) x (1/55) = 1/3025.
#SPJ12
The sum of three products; there are three terms
The product of three sums; there are six terms
The sum of three products; there are six terms
Answer: B The sum of three products; there are three terms
Step-by-step explanation:
The linearfunction is y=2.5x+25
A linear function is a function whose graph is a straightline, that is, a polynomial function of degreezero or one.
As, we know equation of line
y=mx + b
x=number of newspapers
37.5=5m+b...............(1)
also,
75=20m+b....................(2)
Solving (1) and (2) , we get
37.5=15m
m=2.5
and, 75=2.5(20)+b
75=50+b
b= 25
Hence, y=2.5x+25 is linear function.
Learn more about this concept here:
#SPJ5
6x - 15 = -3y
2) 6y + 2x = 8
12y + 4x = 4
The correct classification of the given equations is as follows:
This refers to the system of equations where an equation has infinite solutions and has more than one form on a given line.
With this in mind, we can see that when we are given a system of equations such as
5 - y = 2x
6x - 15 = -3y, then we know that this is a dependent equation because of the infinite solutions on the two equations.
Read more about dependent equations here:
brainly.com/question/10417850
Solution: Each coin toss has 2 possible outcomes "Head" and "Tail". So if we flip a coin four times, the number of possible outcomes are:
outcomes.
Let H denotes the Head and T denotes the Tail, then the 16 possible outcomes are enumerated below:
HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT,
THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT
Answer: 22
Step-by-step explanation: