What is the least common multiple of 49 and 28?

Answers

Answer 1
Answer: least common mulitplue is the smallest number that has 49 and 28 as factors

so to do this
find the factor so 49 and 28 and gropu all of them so both are in it

49=7 times 7
28=2 times 2 times 7
therefor yo need at least two 7's and two 2's
that equals
7 times 7 times 2 itme s2=49 times 4=196

answer is 196
Answer 2
Answer:

Answer:

The least common multiple is 196

Step-by-step explanation:

I had this test I got this question and I got correct.


Related Questions

27÷89,420? may someone please tell me what is the answer?
A rectangular prism has a volume of 432 in3. The height of the prism is 9 in. What are the dimensions of the base?
Reggie has enough flour to last for 40 days. If he increases his use of flour by 25%, however, how many days' worth of flour will he have? A: 30 days B: 28 days C: 32 days D: 48 days
Find the value of y.​
Can you help me with this please

How to solve 30b=$41.10

Answers

When you're looking for the answer, you simply divide both sides by 30.
30b/30= b
$41.10/30= $1.37
When you've got any answers like this, you always have to try and get b alone, and you may also have to add digits, or divide, it varies from each equation.
Hope this helps :) 

divide both sides by 30 and you'll get the value for b.

A person on a moving sidewalk travels 18 feet in 9 seconds. The moving Sidewalk has a length of 80 feet. How long will it take to move from one end to another? The person will take ____ seconds you move from one end to another.

Answers

Answer:

40 seconds

Step-by-step explanation:

9 seconds = 18 feet

x seconds = 80 feet

then cross multiply

(9*80)/18 = x

x = 40

hence time = 40 seconds

Answer:

40 steps

Step-by-step explanation:

Nadia's father bought a new camera,lens, and case. He rounded the cost of all the items to estimate how much money he would need. He rounded the cost of the camera to $800,the cost of the lens to $500, and the cost of the case to $200. The actual cost of all three was 1,489. What could the actual cost of all three items be? Show your work answer for camera,lens,case

Answers

799, 499, and 191. (I got it off the textbook online.)

Final answer:

The actual costs of camera, lens, and case could approximately be $795, $495, and $199 respectively, summing up to the total actual cost of $1,489.

Explanation:

In the question, Nadia's father estimated the cost of her camera, lens, and case to be $800, $500, and $200 respectively. However, the actual total cost of these three items was $1,489. Now, if he rounded the cost of each item, the actual cost of each item could be a bit less or more than the estimated costs. When you sum up the rounded cost of these three items ($800 + $500 + $200), it equals $1,500 which is $11 more than the actual total cost. The overestimation implies that the actual total cost ($1,489) might have been rounded up for one or more of the items. Therefore the actual prices could be something like: $795 for the camera, $495 for the lens, and $199 for the case. Summing these up will give you the actual total cost of $1,489.

Learn more about Rounding here:

brainly.com/question/34045884

#SPJ11

Subtract 72km 200m-48km 600m

Answers

Answer:

m- 14400km2 +28800km

Step-by-step explanation:

Find the additive inverse of −5 + 7i.​

Answers

Answer:

5-7i

Step-by-step explanation:

-5+7i+(5-7i)=0 so 5-7i is the additive inverse of -5+i

hope this helps-

Which quadrilaterals are also parallelograms?Choose all answers that are correct.

A.
square

B.
rhombus

C.
trapezoid

D.
rectangle

Answers

Squaresrhombusesrectanglesare parallelograms

Trapezoids are not