20-15/1-3= 5/-2
x=-2.5
15= 3(-2.5) + b
15=-7.5 + b
b=22.5
X-Intercept= (-2.5,0)
Y-Intercept= (0, 22.5)
The required equation of the line is y = 8 - x.
Given that,
To determine an equation of the line that passes through the point (8,0) and is parallel to the line x+y=5
The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.
Here,
Given equation,
x+y=5
y = -x + 5
m = -1
Since the slope of parallel lines are equals.
So the equation of the line is given as, which is passing by (8,0)
y - 0 = -1 (x - 8)
y = 8 - x
Thus, the required equation of the line is y = 8 - x.
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Answer:
y = -x + 5
y - 0 = - (x - 8)
y = -x + 8
Step-by-step explanation: