What is 4 7/20 written as a decimal?

Answers

Answer 1

Answer: Solve:-

Convert to improper fraction:-

4 7/20
20 × 4 = 80
80 + 7 = 87

Improper fraction:- 87/20

Turn to decimal:-
Divide Numerator by denominator:-

87/20
87 ÷ 20 = 4.35

4 7/20 = 87/20 = 4.35
4 7/20 = 4.35

Answer 2

Answer:

The decimal form of a number 4 7/20 is, 4.35

Now, We can Convert to improper fraction:-

4 7/20

20 × 4 = 80

80 + 7 = 87

Hence, Improper fraction:-

= 87/20

Now, We can Turn into decimal:-

Divide Numerator by denominator:-

87/20

87 ÷ 20

= 4.35

Hence, We get;

4 7/20 = 87/20 = 4.35

4 7/20 = 4.35

Learn more about Number system visit:

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Sofia learned 10 recipes to create party dishes. She learned these recipes in two weeks. How many recipes can Sofia learn in 5 weeks ?

Answers

If she learned 10 in two weeks, that means she learns an average of 5 per week, that means in 5 weeks all you have to do is multiply by 5, the answer is 25 recipes.

10 recipes/2 weeks = 5 recipes/1 week
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Find the rate of commission if total sales are $3600 and the commission is $90

Answers

The answer should be 40%

Answer:

the comission percent is 2.5

Step-by-step explanation:

What expression represents five time the quotient of some number and ten?A: 5 ( 10 - z )
B: 5 ( z / 10 )
C: z ( 10 / 5 )
D: 5 ( z - 10 )

Answers

Answer: B

Step-by-step explanation:

First off, choices A and D can be elimination because you are not subtracting. In choice C, we have 10 divided by 5 as opposed to z divided by 5. The answer is B.

Explain how solve 4^(x+3)=7 using the change of base formula log base b of y equals log y over log b. Include the solution for x in your answer. Round your answer to the nearest thousandth.

Answers

The value of x is -1.596

Solution:

Given equation is:

$4^((x+3)) = 7$

Let us solve using change of base formula log base b of y equals log y over log b

From given,

$4^((x+3)) = 7$

$\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right)$

Therefore,

$\ln \left(4^(x+3)\right)=\ln \left(7\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$\ln \left(4^(x+3)\right)=\left(x+3\right)\ln \left(4\right)\n\n\left(x+3\right)\ln \left(4\right)=\ln \left(7\right)\n$

Let us simplify the above

$\left(x+3\right)\cdot \:2\ln \left(2\right)=\ln \left(7\right)\n\n\mathrm{Divide\:both\:sides\:by\:}2\ln \left(2\right)\n\n(\left(x+3\right)\cdot \:2\ln \left(2\right))/(2\ln \left(2\right))=(\ln \left(7\right))/(2\ln \left(2\right))\n\n$

$\mathrm{Simplify}\n\nx+3=(\ln \left(7\right))/(2\ln \left(2\right))\n\n\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\n\nx+3-3=(\ln \left(7\right))/(2\ln \left(2\right))-3\n\n\mathrm{Simplify}\n\nx=(\ln \left(7\right))/(2\ln \left(2\right))-3$

Substitute the values

ln 7 = 1.9459101490553132

ln 2 = 0.6931471805599453

Therefore,

$x = (1.9459101490553132)/(2 * 0.6931471805599453) - 3\n\nx = 1.40367746103 - 3\n\nx = -1.59632253897 \approx -1.596$

Thus solution for x is found

The first 5 multiples of 2 is that possible

Answers

The first five multiples of 2 are: 2, 4, 6, 8, 10

Explain how you can find the missing number in 3 4/5 divide [ ] = 2 5/7 then find the missing number. I need help now please.

Answers

find the missing number in 3 4/5 divide [ ] = 2 5/7

Let the unknown number be x

$(3 (4)/(5))/(x)=2(5)/(7)$

$3(4)/(5)$ can be written as $(19)/(5)$

$2(5)/(7)$ can be written as $(19)/(7)$

So equation becomes

$((19)/(5))/(x)=(19)/(7)$

We need to get x alone, so we multiply by x on both sides

$(19)/(5)=(19)/(7) *x$

Now to remove 9/7 we take reciprocal and multiply it on both sides

$(19)/(5) * (7)/(19) =(19)/(7)* (7)/(19) *x$

$(7)/(5)=x$

The missing number is $(7)/(5)$

answer is 10 11/35

Because here you are finding an unknown, so you redo the problem.
The problem tells you to divide so the opposite is times the number
so 2 5/7 times 3 4/5 is 10 11/35

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