Answer:
Chemist John Dalton
Coastal ecosystems have less sunlight, fewer nutrients, and less diversity than open ocean ecosystems.
Coastal ecosystems have a greater range of water pressures than open ocean ecosystems.
Coastal ecosystems have more sunlight, more nutrients, and higher levels of productivity than open ocean ecosystems
The statement that best compares coastal ecosystems to open ocean ecosystems is Coastal ecosystems have more sunlight, more nutrients, and higher levels of productivity than open ocean ecosystems.
ecosystems can be regarded as the biological community of interacting organisms as well as their physical environment.
However, there is coastal ecosystems and open ocean ecosystems, but there are more sunlight, more nutrients, and higher levels of productivity in Coastal ecosystems than ocean ecosystems.
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Answer:
I believe the last one is correct Coastal ecosystems have more sunlight, more nutrients, and higher levels of productivity than open ocean ecosystems
An oxidation reaction involves the loss of electrons or an increase in the oxidation state of an element. Options B, C, and D represent oxidation reactions, while option A does not.
Let's analyze the given options:
A. AuCl₄⁻ → AuCl₂⁻
In this reaction, the gold atom goes from a +3 oxidation state (AuCl₄⁻) to a +1 oxidation state (AuCl₂⁻). This means the gold atom gains two electrons, indicating a reduction rather than oxidation. Therefore, option A is not an oxidation reaction.
B. Mn⁷⁺ → Mn²⁺
In this reaction, the manganese atom goes from a +7 oxidation state to a +2 oxidation state. This indicates a decrease in the oxidation state, which means the manganese atom gains electrons. Therefore, option B represents an oxidation reaction.
C. Co³⁺ → Co²⁺
In this reaction, the cobalt atom goes from a +3 oxidation state to a +2 oxidation state. Similar to option B, this indicates a decrease in the oxidation state, representing an oxidation reaction.
D. Cl₂ → ClO₃⁻
In this reaction, the chlorine molecule (Cl₂) is converted to a chlorate ion (ClO₃⁻). Here, the chlorine atom undergoes an increase in oxidation state, changing from an oxidation state of 0 in Cl₂ to an oxidation state of +5 in ClO₃⁻. This indicates the loss of electrons by chlorine, making option D an oxidation reaction.
Therefore, options B, C, and D represent oxidation reactions, while option A does not.
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(1) -153°C (3) +293°C
(2) -120.°C (4) +393°C
The temperature 120 K converts to -153°C. This conversion is made by subtracting 273.15 from the Kelvin temperature.
To convert Kelvin (K) to Celsius (°C), you subtract 273.15 from the Kelvin temperature. For example, 120 K becomes 120 - 273.15, equaling -153.15°C. Rounded, this is approximately -153°C. It's essential to note that 0 K is absolute zero, representing the lowest possible temperature, which corresponds to -273.15°C on the Celsius scale. Therefore, the correct answer is (1) -153°C. This conversion is fundamental in relating temperatures on the Kelvin and Celsius scales, where Celsius measures temperature relative to the freezing and boiling points of water, and Kelvin starts from absolute zero, the absence of thermal energy.
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In an exothermic energy diagram, the reactants side is higher in energy than the product side.
An exothermic reaction is one in which the heat of the reactants is greater than that of the products. In that case, energy is given off in the reaction as heat and the reaction vessel is warmer.
Now, in an exothermic energy diagram, the reactants side is higher in energy than the product side.
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The stoichiometric coefficient for aluminum, Al when the chemical equation is balanced is 2.
To obtain the stoichiometric coefficient for aluminum, we shall write and balance the equation for the reaction. This is illustrated below:
Aluminum => Al
Iron (II) chloride => FeCl₂
Aluminum chloride => AlCl₃
Iron => Fe
Aluminum + Iron (II) chloride —> Aluminum chloride + Iron
Al + FeCl₂ –> AlCl₃ + Fe
There are 3 atoms of Cl on the right side and 2 atoms on the left side. It can be balance by writing 3 before FeCl₂ and 2 before AlCl₃ as shown below:
Al + 3FeCl₂ –> 2AlCl₃ + Fe
There are 2 atoms of Al on the right side and 1 atom on the left. It can be balance by writing 2 before Al as shown below:
2Al + 3FeCl₂ –> 2AlCl₃ + Fe
There are 3 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 3 before Fe as shown below:
2Al + 3FeCl₂ –> 2AlCl₃ + 3Fe
Now, the equation is balanced.
The coefficient of Aluminum, Al in the balanced equation is 2.
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Answer:
2.
Explanation:
2Al(s) + 3FeCl₂(aq) → 2AlCl₃(aq) + 3Fe(s).
It is clear that 2 mol of Al react with 3 mol of FeCl₂ to produce 2 mol of AlCl₃ and 3 mol of Fe.