The second term of this given geometric series is
A geometric sequence's finite or infinite terms are added together to form a geometric series. The geometric series that corresponds to the geometric sequence a, ar, ar2,..., arn-1,... is a + ar + ar2 +..., arn-1 Clearly, "series" means "sum." The phrase "geometric series" refers specifically to the total of words with a common ratio between every adjacent pair of them. Finite and infinite geometric series are both possible.
Given a geometric series 1/4 + × + 1/36 + 1/108 +.....
In this series first term(a) = 1/4
second term(a₂) = x
Third term (a₃) = 1/36
ratio(r) = a₄ /a₃
ratio (r) = 1/3
The formula for the nth term of a geometric series is aₙ = arⁿ⁻¹ .....(1)
put these values in equation (1)
a₂ =
a₂ = 1/12
Hence, the second term for the geometric series 1/4+×+1/36+1/108+... is 1/12.
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Answer: 509,082
Step-by-step explanation:
2/3 / 8/7 flip the second fraction and multiply straight across
2/3 x 7/8 2 x 7 = 14
3 x 8 = 24 so you have 14/24 if you need to simplify, since both numerator and denominator are even so divide by 2. Which gives you 7/12
Hope this helps you :)
To solve that you're gonna have to multiply 2/3 by the reciprocal of 8/7 which is 7/8.
2/3 * 7/8 = (2 * 7)/(3 * 8)
14/24 reduces to 7/12 or .5833
Answer:
B: $1450
Step-by-step explanation:
The delivery truck can travel 738 miles on 41 gallons of gas, assuming it maintains the same fuel efficiency. This is calculated by first finding the mileage per gallon (miles driven divided by gallons used), then multiplying that by the number of gallons.
The situation given can be solved by using unit rate or sometimes referred to as proportion. The delivery truck traveled 324 miles on 18 gallons of gas. We'll first find out the mileage per gallon and then use that to compute how far it could go on 41 gallons.
So, a delivery truck that traveled 324 miles on 18 gallons of gas could travel 738 miles on 41 gallons of gas, assuming the truck maintains the same fuel efficiency.
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