Answer:
Sun is cm away from alpha century.
Sun is m.
Sun is 1.391016 time the size of an atom at this scale.
Step-by-step explanation:
Light year is a measure of distance. It is the distance light travels in an year.
Light year = km
So 4.4 light years = km
km
Lets scale this down to the level of
km
= km
Change the units to centimeters:
cm
= cm
= cm
Therefore on the new scale sun is cm away from alpha century.
Diameter of the sun is 1.391016 million km
Lets change Sun's diameter to the new scale:
km
=km
Lets change kilometers in to meters:
m
=m
Therefore, sun is m
and an atom is
Therefore the sun is 1.391016 time the size of an atom at this scale.
On a 1-to-10^19 scale, the distance from the Sun to the Alpha Centauri is about 44 cm. On this same scale, the Sun itself would have a diameter of about 150 picometers, which is larger than a typical atom.
The 1-to-10^19 scale means for every actual meter in space, we represent 10^19 meters on our model. The Alpha Centauri is 4.4 light-years away from the sun. Considering 1 light-year equals to approximately 9.46x10^15 meters, the real distance from the sun to Alpha Centauri is about 4.16x10^16 meters. So, on the scale, this is about 0.44 meters or 44 cm.
The Sun's real size, with a diameter of 1.5 million kilometers or 1.5x10^9 meters, is represented as 1.5x10^-10 meters or 150 picometers on the scale. This is much bigger than an actual atom, which has a diameter of 0.1 to 0.5 nanometers or 100 to 500 picometers. Hence, on this scale, the Sun would be larger than a typical atom.
#SPJ11
B. x < 10 or x > 8
C. x < 8 and x > 10
D. x < 10 and x > 8
Answer:
The answer is the option A
or
Step-by-step explanation:
we know that
The interval -----> (-∞,8)
Is all real numbers less than
The interval -----> (10,∞)
Is all real numbers greater than
The expression (-∞,8) U (10,∞) represent the inequality
or
see the attached figure to better understand the problem
Answer:
6.40
Step-by-step explanation:
Answer: 30 different pairs of collectors will trade rocks
Step-by-step explanation:
Andy,bette,cate,dustin,erik,and franco are six in number
Since each collector is going to trade with every other, the different way of trade will be 6 permutation 2
6P2 = 6!/(6-2)! = (6×5×4!)/4! = 6×5 = 30 ways
Therefore 30 different pairs of collectors will trade rocks
x^2-2x-5=0
Answer:
Step-by-step explanation:
Ray hired sun and peter to help him move.
Let h represent the number of hours that each of them worked.
Let y represent Ray's total cost for hiring Sun and Peter for h hours.
Sun charged a $20 flat fee and $30 per hour. The total amount that Sun charges would be
20 + 30h
Peter charged $25 per hour. The total amount that Peter charges would be
25h
An expression for Ray's total cost if Sun and Peter each work h hours would be
y = 20 + 30h + 25h
y = 20 + 55h
Answer:
[20+(30+25)]h or (20+55)h
Step-by-step explanation:
20 will not be changed.
Total cost per hour is 55
add $20
Hope this helps