To calculate the number of grams of copper (Cu) in 2.55 mol of Cu, multiply the number of moles by the molar mass of copper. The molar mass of Cu is 63.55 g/mol. Therefore, there are 162.05 grams of copper (Cu) in 2.55 mol of Cu.
To calculate the number of grams of copper (Cu) in 2.55 mol of Cu, we need to use the molar mass of copper. The molar mass of Cu is 63.55 g/mol. Therefore, 2.55 mol of Cu is equal to:
2.55 mol Cu × 63.55 g/mol = 162.05 g Cu
So, there are 162.05 grams of copper (Cu) in 2.55 mol of Cu.
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What occurs when the concentration of H2(g) is increased?
(1) The rate of the forward reaction increases and the concentration of N2(g) decreases.
(2) The rate of the forward reaction decreases and the concentration of N2(g) increases.
(3) The rate of the forward reaction and the concentration of N2(g) both increase.
(4) The rate of the forward reaction and the concentration of N2(g) both decrease.
If the concentration of is increased, the rate of the forward reaction increases and the concentration of decreases.
The principle states that reactions in equilibrium being disturbed by factors such as temperature, the concentration of species in the reaction, etc, will experience a shift in the equilibrium so as to annul the effects of the disturbance.
Thus, adding more of the reactants ( to the reaction will see more products being synthesized. This means more will be consumed and its concentration will decrease accordingly.
More on Le chartelier principle can be found here: brainly.com/question/12099569
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Each shift worked can pay for 3.75 loads of laundry if each load costs 16 quarters.
This problem can be solved using simple dimensional analysis. The steps are:
STEP 1: Sort first the given in the problem to identify possible conversion factors to be used in the dimensional analysis.
The following equalities are given in the problem:
STEP 2: From these equalities, the following dimensional analysis can be set up:
Therefore, one shift can pay for 3.75 loads of laundry.
Keywords: dimensional analysis, problem solving
B. farmer
C. painter
D. carpenter
B) Arrhenius bases
C) Brønsted-Lowry bases
D) Brønsted-Lowry acids
Answer:
tendons and ligaments