Is 14.114 greater or less than 141.14 or =

Answers

Answer 1
Answer: no 14.114 is lesser than 141.14
Answer 2
Answer: neither. it's less than

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A box contains bags of crisps. Each bag of crisps weighs 25 grams. Altogether, the bags of crisps inside the box weigh 1 kilogram. How many bags of crisps are inside the box?

Answers

there would be 40 bags
There are 40 bags total

Is 100 feet greater or less than 3 yard

Answers

1yard=3feet

So for it to be even, you need 33.33 yards

But there is only 3 yards so that means 100 feet is greater

Even if you did a mistypo and meant 10 feet, it would still be greater than 3 yards
100 feet is fairly way bigger than 3 yards

Simplify (3xy) to 6th power

Answers


You can write that expression in many different ways,
but you won't find one that's any simpler than (3xy)⁶ .

Here are a few:

(3)⁶x⁶y⁶
729x⁶y⁶
(27x³y³)²
(3x)⁶y⁶
(3y⁶)x⁶



(0.5x - 4 - (1.5x + 2.3)

Answers

Answer: 1/10(-10x-63)

Step-by-step explanation:

1) decimals to fractions

1/2x-4-(3/2x+23/10)

2) factor

1/2(x-8)-1/10(15x+23)

3) factor out 1/10

1/10[5(x-8)-(15x+23)]

4) distribute 5 through ()’s

1/10(5x-40-15x-23)

5) collect like terms

1/10(-10x-63)

How do you find the perimeter of a dented square HERE IS THE PIC....

Answers


To find the perimeter of anything, you look at it and figure out how far
an ant has to walk if you put it down at one corner, and it walks all the way
around all the edges until it gets back to where it started.

On this square with a bite cut out of it, I see three x's and three 1's that
the ant has to walk.  That looks a lot like   3x+3  to me.

A piece of wood that is 3/4 meter long is being cut into smaller pieces that are each 1/10 meter long. Which equation could be solved to find the number of pieces, n, that can be made?A. n = 3/4 x 1/10
B. n = 3/4 x 10/1
C. n = 10/1 x 4/3
D. n = 1/10 x 4/3

Answers

The answer is B.
You would want to do (3/4) / (1/10) which is the same as (3/4) * (10/1) or option B.

Answer:

Idk

Step-by-step explanation:

I dont know da answer, bro.