What is the exact area of a circle with a diameter of 25 pi m?A. 25 pi m²


B. 50 pi m²


C.156.25 pi m²


D. 625 pi m²

Answers

Answer 1
Answer: The rule to figuring out the area of a circle is A=r^2*pi. 

So since the radius is half of the diameter you will ne to cut 25 in half. Which equals 12.5. OK so now we need to multiply 12.5 by 12.5 which equals 156.25.

So i believe that the Answer is C. 156.25pi m^2
Answer 2
Answer: Diameter = radius * 2
25 = radius * 2
radius = 12.5

Area = radius^2 * pi
Area = 12.5^2 * pi

Area = 156.25 pi m^2

Your answer is C.

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How can you determine the coordinates of any image that is dilated with the center of dilation at the origin without graphing? Explain your reasoning.

Answers

Answer:

The image of point (x , y) by dilation with center origin and scale factor k is (kx , ky)

Step-by-step explanation:

* Lets talk about dilation

- A dilation is a transformation that changes the size of a figure.  

- It can become larger or smaller, but the shape of the

 figure does not change.  

- The scale factor, measures how much larger or smaller  

  the image will be

- If the scale factor greater than 1, then the image will be larger

- If the scale factor between 0 and 1, then the image will be smaller

* In a problem  of dilation

∵ The center of dilation is the origin

∵ The scale factor of dilation is k

∵ The point is (x , y)

- In dilation with center origin and scale factor k to find the image

 of the point multiply each coordinates of the point by the scale

 factor k because the distance d between the point and the

 origin will be equal kd which is the distance between the origin

 and the image of the point d is depending on the coordinates

 of the point

The image of point (x , y) by dilation with center origin and

   scale factor k is (kx , ky)

* Ex: If point A is (3 , 4)

∵ The distance from the origin to point A = \sqrt{(3)^(2)+(4)^(2)}=√(9+16)=√(25)=5

∵ The scale factor of dilation is 2 and the center is the origin

∴ The image of A is A' = (3 × 2 , 4 × 2) = (6 , 8)

∵ The distance from the origin to point A' = \sqrt{(6)^(2)+(8)^(2)}=√(36+64)=√(100)=10

∵ 10 ÷ 5 = 2 which is the value of the scale factor

The image of point (x , y) by dilation with center origin and

   scale factor k is (kx , ky)

What is 1/10 of 3,000

Answers

1/10 of 3000 is equal to 300

Answer:

300

Step-by-step explanation:

You take your 3000 and write it down. When you are dividing numbers and fractions, you divide by the bottom and multiply by the top. Following this, we know that 1/10 is equal to divided by 10.  You now go back to that paper and look at your 3000. Divided by 10 is just moving the decimal point one to the left. that leaves you with 300.0, or 300.

David has 5400000 females he destroys 4 of them how many dose he have

Answers

Answer:

sorry no answer of that man

Step-by-step explanation:

i haerd efan seggy has answer

5,399,999 Bc 5400000 - 4 is 5399999

Maria read 3,356 pages in july and read 2,349 pages in August how many more pages did she read in july than in August?

Answers

3,356 - 2,349 = 1,007

So she read 1,007 more pages in July than in August
1,007 is the answer to your subtraction prob.

Jack and Rock agree to meet in London for the weekend. Jack travels 164 miles and Rock travels 106 miles. If Jacks rate of speed is 8 mph faster than Rock’s then at what rate of speed does Jack travel?

Answers

v=(s)/(t)\n\nv-velocity;\ s-distance;\ t-time\n\nv=(s)/(t)\to vt=s\to t=(s)/(v)\n---------------------\nv-Rock's\ veloocity\ (mph)\nv+8-Jack's\ velocity\ (mph)\ns_J=164\ mi-Jack's\ distance\ns_R=106\ mi-Rock's\ distance\nt_J=t_R-times\ are\ equal\n\ntherefore:(s_R)/(v)=(s_J)/(v+8)\n\nsubtitute\ values\ of\ distance:

(106)/(v)=(164)/(v+8)\ \ \ \ |cross\ multiply\n\n106(v+8)=164v\n\n106v+848=164v\ \ \ \ |subtract\ 106v\ from\ both\ sides\n\n848=58v\to 58v=848\ \ \ |divide\ btoh\ sides\ by\ 58\n\nv\approx14.6\ (mph)\n\nAnswer:\boxed{v+8=(14.6+8)mph=22.6\ mph}

Find the quadratic regression for (-1,1) , (0,0) , (1,1)

Answers

3 points define a parabola, so the regression will be unique. You want to find a quadratic polynomial P_2(x)=\beta_0+\beta_1x+\beta_2x^2 such that

\begin{cases}\beta_0-\beta_1+\beta_2=1\n\beta_0=0\n\beta_0+\beta_1+\beta_2=1\end{cases}

where the system above is generated by setting P_2(-1)=1, P_2(0)=0, and P_2(1)=1.

Since \beta_0=0, we have

\begin{cases}-\beta_1+\beta_2=1\n\beta_1+\beta_2=1\end{cases}\implies2\beta_2=2\implies\beta_2=1\implies\beta_1=0

So the regression for the given data points is P_2(x)=x^2.