When multiplying exponents, what do you do when both the exponent and the base are different?

Answers

Answer 1

Answer: Oh wait now i know what you mean, when you see the exponent you multiply the base by the same number that it is by the exponent.
Example:
10(8)
10*10*10*10*10*10*10*10 You multiply 10 by its self 8 times. Hope this helps! :D

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What is $15.60 - $11.70 in in percent

Answers

15.60-11.70 in percent is 6.084 %.

Which value for x makes the sentence true?13x - 8x = 10

A.3
B.2
C.4
D.8

question from study island

Answers

Subtract 8x from 13x to get 5x.
5x=10

Divide each term in the equation by 5.
5x/5=10/5

x=10/5

Divide 10 by 5 to get 2.

x=2

Find the value of the missing trigonometric ratio of each triangle? help me HURRY!!!

Answers

Answer:

The value of cosA = (√3)/2 and tanA = 1/√3 or (√3)/3.

Step-by-step explanation:

Firstly,youhavetofindthevalueofadjacentusingPythogoras'Theorem,a²=b²+c²:

Let a = 2, b = 1

2² = 1² + c²

c² = 2² - 1²

= 4 - 1

= 3

c = √3

NowwehavefoundtheadjacentsowecanfindcosAandtanAusingTrigonometricfunction,cosθ=adj./hypo.andtanθ=oppo./adj.:

adj. = √3

oppo. = 1

hypo. 2

cosA = (√3)/2

tanA = 1/√3 OR (√3)/3

Thanks it saysA fifth grade class collected data about class spending per month on various items. Below are some of the results

A median amount of 6$ per month was spent for books

10 for paper

8 for pencils

6 x
7 x
9 xx
10 xxxx
11 xxxx
12 x
15 x

Answers

Here is what i THINK it wants: I think that each x represents the number of each material purchased and what you are looking for is the frequency at which each item was bought each month. Again, this is my guess but this question is very strange.

I believe that the number of students are the numbers on the left and the x's are amount ($6) spent that month so I multiplied the amount of students with the number of X's or 6 and I found the there are 70 students in this and all together they spent $27780 in 4 months.

WHAT IS S=2PIR^2+2PIRH SOLVE FOR H

Answers

$\n~\qquad\quad S\ =\ 2PIR^2+2PIRH\n\underline{-2PIR^2\qquad-2PIR^2\qquad\quad\ }\n\n S-2PIR^2=2PIRH\n\n 2PIRH\ =\ S-2PIR^2\n\underline{ :(2PIR)\qquad :(2PIR)}\n\n\n H=(S-2PIR^2)/(2PIR)\n\n\n H=(S)/(2PIR)-(2PIR^2)/(2PIR)\n\n\n H=(S)/(2PIR)-R$

or:

$\n~\qquad\quad S\ =\ 2PIR^2+2PIRH\n\n~\qquad\quad S\ =\ 2PIR(R+H)\n\underline{:(2PIR)\qquad :(2PIR)}\n\n\n~\ \ (S)/(2PIR)\ =\ R+H\n\n\n (S)/(2PIR)-R=H\n\n\n H=(S)/(2PIR)-R$

over the last 50 years, the average temperature has increased by 2.5 degrees worldwide. what is the rate of change in worldwide temperatures per year?

Answers

Answer:

0.05 degrees per year

Step-by-step explanation:

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