PLEASE HELP !!! Which polygon is a concave octagon?

Answers

Answer 1
Answer:

The correct answer is:

C. The polygon with 8 sides and a concave shape (attached)

|Huntrw6|


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Simplify: 8x - 6(5x + 6)

9.675,9.25,9.325,9.5 least to greatest

Answers

9.25, 9.325, 9.5, 9.675
9.25, 9.325, 9.5, and 9.675

All equation of motion with examples

Answers

Answer:

Answer is below. Hope this helps you!

Step-by-step explanation:

(i)v = u + at

(ii) s = ut + 1/2 *at²

(iii)2as = v²-u²

Examples:

A train starting from rest attains a velocity of 72km/h in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and  (ii)  the distance travelled by the train for attaining this velocity.

72km/h = 20m/s

(i) use v= u+ at

20 = 0 + a*300

20 = 5a

20 / 300= a

1/15 ms² = a

to find distance

use 2as= v²-u²

2 *1/15 * s = (20) - 0²

2/15s = 400

s = 400 * 15/2

s = 3000m = 3 km

a car accelerates with a uniform acceleration of 1m/s². it starts with a  velocity of 18km/h and reaches 36 km/h in 5 seconds find the distance travelled.

18 km /h = 5m/s

36km/h = 10m/s

use - s= ut + 1/2at²

s = 5 * 5 + 1/2 * 1 * (5)²

s = 25 + 25/2

s = 37.5 meters

Answer:

It is described in terms of displacement, distance, velocity, acceleration, time and speed. Jogging, driving a car, and even simply taking a walk are all everyday examples of motion.

...

The three equations are,

v = u + at.

v² = u² + 2as.

s = ut + ½at²

in one baseball season, peter hit twice the difference of the number of home runs alice hit and 6. altogether, they hit 18 home runs. hohw many home runs did each player hit that season?

Answers

Let Peter's hit be x and Alice's runs be y.
x = 2(y - 6) . . . (1)
x + y = 18 . . . (2)

Putting (1) into (2) gives,
2y - 12 + y = 18
3y = 18 + 12 = 30
y = 30/3 = 10
x = 2(10 - 6) = 2(4) = 8

Therefore, Peter hit 8 home runs and Alice hit 10 home runs.

Evaluate : (25)^1/2. Please solve.

Answers

Answer: 5

Use formula:
\textbf{a^{(m)/(n)} = \sqrt[n]{a^(m)}}

Then you’ll get:
, and this is equal to 5.

The probability for success of an event is P(A), and the probability of success of a second event is P(B). What is the probability of both events occurring, in that order?A. P(A + B)
B. P(A) • P(B)
C. P(A) + P(B)
D. P(A x B)

Answers

Answer:  The correct option is (B) P(A) • P(B).

Step-by-step explanation:  Given that the probability for success of an event is P(A) and the probability of success of a second event is P(B).

We are to find the probability of both events occurring, in that order.

We know that

if two events are independent of each other, then the probability of the intersection of the two events is given by the product of the probabilities of the events.

Here, the event that both events occur is given by (A ∩ B).

And, so the probability of both events occurring, in that order will be

P(A\cap B)=P(A).P(B).

Thus, the required probability is P(A) • P(B).

Option (B) is CORRECT.

D. P(A x B)

To work out the success of both events you have to multiply them together. I'd seriously reccomend learning this rule as it's very important later on in mathematics as it's basically the foundation of all probability statistics.

Determine the equation of the line, in point-slope form, that will get your spacecraft from Point A (0,3) to Point B (-3,0)

Answers

A (0,3), \ \ B (-3,0) \n\n\n First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \n \nm=( 0-3)/(-3-0) = (-3)/(-3)=1 \n \n Use \ point \ form \ of \ a \ line\ with \ one \ point: \n \n y-y_(1) =m(x-x _(1)) \n \nm=1,\ \ x_(1)=0, \ \ y_(1)=3 \n \n y-3= (x-0}\n\ny= x +3
m= (y2-y1)/(x2-x1)

m= (0-3)/(-3-0)

m= (-3)/(-3)

m=1

Point Slope Form:  (y-y1)=m(x-x1)

(y-3)=1(x-0)

(y-3)=(x-0)

(y-3)=(x)