The planet earth orbits around the sun and also spins around its own axis. 33% part (a) calculate the angular momentum of the earth in its orbit around the sun in kg • m2/s

Answers

Answer 1

Answer: The angular momentum can be found by the formula:
L = m · v · r

Where:
m = mass of Earth = 5.972×10²⁴ kg
v = velocity of Earth around the Sun = 2.978×10⁴ m/s
r = distance from Sun = 1.496×10¹¹ m

Now, apply the formula:
L = 5.972×10²⁴ · 2.978×10⁴ · 1.496×10¹¹
= 2.661×10⁴⁰ kg·m²/s

The angular momentum of Earth in its motion around the Sun is 2.661×10⁴⁰ kg·m²/s.

Answer 2

Answer:

Is known:

m = Earth's mass = 5.972 × 10²⁴ kg

v = the speed of the Earth around the Sun = 2,978 × 10⁴ m / s

r = distance from the Sun = 1.496 × 10¹¹ m

Asked:

Answer:

L = m · v · r

L = 5,972 × 10²⁴ · 2,978 × 10⁴ · 1,496 × 10¹¹

L = 2,661 × 10⁴⁰ kg · m² / s

So, the angular momentum of the Earth in its motion around the Sun is 2.661 × 10⁴⁰ kg · m² / s.

Further Explanation

In physics, momentum is a quantity related to the velocity and mass of an object. in classical mechanics, momentum (denoted by P) is defined as the product of mass and velocity, thus producing vectors.

The momentum of an object (P) having mass m and moving with velocity v is defined as:

P = mv

Mass is a scalar quantity, while velocity is a vector quantity. Multiplication of scalar quantities with vector quantities will produce vector quantities. So, momentum is a vector quantity. The momentum of a particle can be seen as a measure of the difficulty of settling an object. For example, a heavy truck has greater momentum than a light car that moves at the same speed. Greater force is needed to stop the truck compared to a lightweight car in a certain amount of time. (The magnitude of mv is sometimes expressed as linear momentum of the particle to distinguish it from angular momentum).

Speed is a vector quantity that shows how fast an object is moving. The magnitude of this vector is named speed and is expressed in units of meters per second (m / s or ms − 1). The mass may be a property of an object that's accustomed to explain the varied behaviors of the item being monitored. In everyday use, mass is typically synonymous with weight. But in keeping with modern scientific understanding, the burden of an object is caused by the interaction of mass with the field

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Details

Grade: College

Subject: Physics

keywords: momentum

Related Questions

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Which techniques can scientists use to determine the characteristics of Earth's layers? Select the two correct answers.examine the behavior of minerals at extremely low temperatures
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Answers

Final answer:

Scientists can determine the characteristics of Earth's layers by studying seismic waves and drilling deep mines to obtain samples from the mantle and core.

Explanation:

The two correct techniques that scientists can use to determine the characteristics of Earth's layers are studying how seismic waves travel through different layers and drilling deep mines to obtain samples from Earth's mantle and core. By studying seismic waves, scientists can analyze their behavior and characteristics as they pass through different layers of the Earth, providing valuable information about their composition and structure. Additionally, drilling deep mines allows scientists to directly access and analyze samples from the Earth's deeper layers, providing insights into the composition and properties of the mantle and core.

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Convert 56km/h to m/s.

Answers

Explanation:

15.556 metres per second

If Jim could drive a Jetson's flying car at a constant speed of 490 km/hr across oceans and space, approximately how long (in millions of years, in 106 years) would he take to drive to a nearby star that is 4.5 light-years away? Use 9.461 × 1012 km/light-year and 8766 hours per year (365.25 days). unanswered

Answers

Answer:

109.5 million years

Explanation:

The question asked us to find the time.

Remember that

Rate of velocity = distance / time, and this,

time taken = distance/rate

Due to the confusing nature of the units, we would have to be converting them to a more uniform one.

1 km is equal to 9.461*10^12 km/light-year, that's if we try to convert km to light year.

Since the speed is in km, the distance has to be in km also, and therefore, we convert ly to km:

4.5 light-years = 9.461*10^12 km/light-year) = 42.57*10^13 km

We that this value as our distance, in km.

Also,

Time = distance/speed

Time = 45.57*10^13 km / 490 km/hr = 9.3*10^11 hr

Now the next step is to convert hours to years, using the conversion factor 8766 hr/yr.

time (in years) = 9.6*10^11 hr / 8766 hr/yr) = 10.95*10^7 years

the final step is to divide the time in years by 10^6 years/million years, which gives the final answer as the trip takes 109.5 million years.

A propeller is modeled as five identical uniform rods extending radially from its axis. The length and mass of each rod are 0.777 m and 2.67 kg, respectively. When the propellor rotates at 573 rpm (revolutions per minute), what is its rotational kinetic energy?

Answers

The formula for the rotational kinetic energy is

$KE_(rot) = (1)/(2)(number \ of\ propellers)( I)( omega)^(2)$

where I is the moment of inertia. This is just mass times the square of the perpendicular distance to the axis of rotation. In other words, the radius of the propeller or this is equivalent to the length of the rod. ω is the angular velocity. We determine I and ω first.

$I=m L^(2)=(2.67 \ kg) (0.777 \ m)^(2) =2.07459 \ kgm^(2)$

ω = 573 rev/min * (2π rad/rev) * (1 min/60 s) = 60 rad/s

Then,

$KE_(rot) =( (1)/(2) )(5)(2.07459 \ kgm^(2)) (60\ rad/s)^(2)$

$KE_(rot) =18,671.31 \ J$

Answer:

4833J

Explanation:

Length=0.777

mass=2.67

# rods= 5

ω=573 rpm--> $573*2\pi *(1)/(60) =60$ rad/s

I= $(1)/(3) mL^2=(1)/(3) (2.67kg)(0.777m)^2=0.537$ kgm^2

K=1/2(number of rods)(I)(ω)= $(1)/(2) *(5)(0.537)(60)^2=4833$ J

I know it's very late, but hope this helps anyone else trying to find the answer.

Let A be the last two digits, and let B be the last three digits, and the C be the sum of the last 4 digits of your 8-digit student ID. (Example: For 20245347, A = 47, B = 347, and C = 19) A train moves at an average speed of (23.0 + A) m/s for (250.0 + B) seconds and then at an average speed of (45.0 + C) m/s for (800.0 + B) seconds. Determine the average speed for the entire time in meters per second (m/s). Round your final answer to 3 significant figures.

Answers

Answer:

66.053m/s

Explanation:

A = 47

B = 347

C = 19

Train moves at

(23 + A)m/s

= 23 + 47 = 60m/s

At (250.0+B) seconds

250.0+347 =

547 seconds

Distance d,

= 70 x 597

= 41790

It also moves at

(45.0 + c)

= 45 + 19

= 64m/s

Time = 800 + B

= 800 + 347

= 1147

Distance,

= 64 x 1147

= 73408m

Total distance,

= 73408 + 41790

= 115,198

Total time,

= 597 + 1147

= 1744

Average speed,

= Total distance / total time

= 115198/1174

= 66.053m/s

Final answer:

The average speed over the entire time can be calculated by first finding the distances the train travels over both periods, then finding the total distance and the total time, and finally dividing the total distance by the total time. The value must be rounded to three significant figures.

Explanation:

You can find the average speed of the train over the full-time interval by dividing the total distance travelled by the total time. To begin with, you would have to find the distances the train covered during both periods.

The distance (D1) it travelled during the first period can be found by multiplying the average speed (23.0 + A) by the time (250.0 + B).
The distance (D2) it travelled during the second period can be calculated by multiplying the average speed (45.0 + C) by the time (800.0 + B).

Then you add D1 and D2 to get the total distance (TD). This will be (D1 + D2). The total time (TT) will be found by adding both time intervals, which means it equals (250.0 + B) + (800.0 + B). You then divide the total distance by the total time to get the average speed, i.e., TD/TT. Lastly, round the average speed to 3 significant figures.

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A water-skier is being pulled by a tow rope attached to a boat. As the driver pushes the throttle forward, the skier accelerates. A 76.2-kg water-skier has an initial speed of 5.0 m/s. Later, the speed increases to 10.4 m/s. Determine the work done by the net external force acting on the skier.