MATHEMATICS COLLEGE

*An isosceles trapezoid ABCD has bases AD = 17cm, BC = 5cm, and leg AB = 10 cm. A line is drawn through vertex B so that it bisects diagonal AC
and intersect
AD
at point M. Find the area of ΔBDM. What is the area of ABCD?

Answers

Answer 1
Answer:

The diagram is attached below

The midpoint of AC is E. The ΔMAE is congruent to ΔBCE, and the sides MA = BC = 5 cm. Also MD = 17 -5 = 12 cm

From the figure we can see that the height of the trapezoid is 8cm

The height of trapezoid is the difference between the x axis and the BC that is 8cm

The triangle BDM has base 12 cm and height 8 cm.

Area of triangle = (1)/(2) * base * height

A = (1)/(2) * 12 * 8 = 48 cm²

2. The area of trapezoid ABCD formula is

A = (base_1 + base_2)/(2)* height

base 1= 17cm , base2= 5cm , height = 8cm

A = (17 + 5)/(2)* 8

A = 88 cm²
Answer 2
Answer: Asked and answered elsewhere.
brainly.com/question/9635743

Related Questions

How are the lizard and the spider part of the same food web??
Janice is studying the effect of pipe size on water flow rates. In12 minutes, 463.2 gallons of water flowed from a 2-inch pipe. In7 minutes, 1730.4 gallons of water flowed from a 4-inch pipe.Based on Janice's data, what is the difference in flow ratebetween a 2-inch and 4-inch pipe?​
Find the value of a. Then find the angle measures of the quadrilateral.
the average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2 . three scores extracted from the test are 148,102,152. What is the average of the extracted scores that are extreme values. ​
Your office is raising money for charity by collecting aluminium cans for recycling. They get 36p per kilo of cans. A kilo is approximately 72 cans. They have collected 8645 cans How much money have they raised?

James is 10 feet below sea level if he increases his elevation by 30 feet what is his location?

Answers

His location would be 20 feet above the sea level because...

30+-10= 20 because adding a negative to a positive is basically like subtracting.

Can have a brainliest answer now please?

At a computer store, a customer is considering 9 different computers,10 different monitors,8 different printers and 2different scanners. Assuming that each of the components is compatible with one another and that one of each is to be selected. Determine the number of different computer systems possible.

Answers

Answer:

The number of different computer systems possible is 1440.

Step-by-step explanation:

For each computer, there are 10 options of monitor.

For each monitor, there are 8 printers.

For each printer, there are 2 scanners.

There are 9 computers.

Determine the number of different computer systems possible.

9*10*8*2 = 1440

The number of different computer systems possible is 1440.

What is the solution to the following inequality X/-2 > 5

Answers

Answer:

x < -10

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

x/-2 > 5

Step 2: Solve for x

  1. [Multiplication Property of Equality] Multiply -2 on both sides:                     x < -10

\large {\mathsf {\red{\underbrace {\overbrace{\blue{ {\pink}{Answєr}}}}}}} \:

x > - 10

\large \mathtt \green{Step-by-step \: explanation : }

\small \sf (x)/( - 2) > 5 \n

Solve forx

\small \sf (x)/( - 2) > 5 \n

common denominator is 2

\small \sf ➪ (2x)/( - 2) >2 * 5 \n

\small \sf ➪ \frac{ \cancel{2}x}{ - \cancel{ 2}} >2 * 5 \n

➪ - x > 2 × 5

➪ - x > 10

multiply by - 1

➪ - x × - 1 > 10 × - 1

x > - 10

Consider the point.(4, 5, 6)
What is the projection of the point on the xy-plane?
(x, y, z) =__________.

What is the projection of the point on the yz-plane?
(x, y, z) =________

What is the projection of the point on the xz-plane?
(x, y, z) =___________

Answers

Answer:

(4,5,0)

(0,5,6)

(4,0,6)

Step-by-step explanation:

The projection of the point on the plane can be determined as:

xy-plane, z=0.

(x,y,z)=(x,y,0)=(4,5,0)

yz-plane, x=0.

(x,y,z)=(0,y,z)=(0,5,6)

xz-plane, y=0.

(x,y,z)=(x,0,z)=(4,0,6)

RESOLVER LOS SIGUIENTES SISTEMAS DE ECUACIONES APLICANDO EL METODO DE SUSTITUCION2x +3y = 2
-6x + 12y = 1

Answers

Answer:

x = 1/2; y = 1/3

Step-by-step explanation:

2x + 3y = 2     Eq. 1

-6x + 12y = 1     Eq. 2

Eq. 1

2x + 3y = 2

2x = -3y + 2

x = -3/2 y + 1

Eq. 2

-6x + 12y = 1

De Eq. 1 sabemos que x = -3/2 y + 1

-6x + 12y = 1

-6(-3/2 y + 1) + 12y = 1

9y - 6 + 12y = 1

21y - 6 = 1

21y = 7

y = 7/21

y = 1/3

Eq. 1

2x + 3y = 2

2x + 3(1/3) = 2

2x + 1 = 2

2x = 1

x = 1/2

Respuesta: x = 1/2; y = 1/3

On two investments totaling $6,000, Kevin lost 3% on one and earned 6% on the other. If his net annual receipts were $288, how much was each investment?

Answers

ANSWER:

$ 800 was invested in the account at 3%

$5200 was invested in the account at 6%

STEP-BY-STEP EXPLANATION:

We can establish the following system of equations thanks to the help of the statement:

Let x represent the amount invested in the investment that lost value

Let y represent the amount invested in the investment that gained

value.

\begin{gathered} x+y=6000\rightarrow y=6000-x\text{ (1)} \n -0.03x+0.06y=288\text{ (2)} \end{gathered}

We replace equation (1) in (2) and solve for x:

\begin{gathered} -0.03x+0.06\cdot(6000-x)=288 \n -0.03x+360-0.06x=288 \n -0.09x=288-360 \n x=(-72)/(-0.09) \n x=800 \n \text{ Now, for y replacing in (1)} \n y=6000-800=5200 \end{gathered}

Therefore, $ 800 was invested in the account the lost value, and $ 5200 was invested in the account that gained value.
Other Questions
Part BComplete the table for the clementines in units of pounds and cost.В І оFont SizesАА -Pounds CostIIO
Help find the circumstance and area
.I’ll give you a brainliest to whoever does itSimplify by combine like terms3X+4Y+5X-2y+10-8
How do you write 1.8 × 10^1 in standard form?