Anna is constructing a line segment that is congruent to another segment AB. For the construction, which tool should be used to mesure segment AB

Answers

Answer 1

Answer:

Straight edge and a compass are tools used to measure segment AB

What is Geometry?

Branch of mathematics concerned with the shape of individual objects, spatial relationships among various objects, and the properties of surrounding space.

Given that Anna is constructing a line segment that is congruent to another segment AB.

For the construction, we need to find which tool should be used to measure segment AB.

Most constructions are just done with a straight edge and a compass.

A compass setting is used to measure the length of a segment in a

You would use the compass to measure the length of the segment. Just open the compass from one endpoint to the other. Then, you can use that to draw a congruent line segment.

Hence, A compass setting is used to measure the length of a segment.

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Answer 2

Answer: Most constructions are just done with a straight edge and a compass.

You would use the compass to measure the length of the segment. Just open the compass from one endpoint to the other. Then, you can use that to draw a congruent line segment.

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Answers

the coefficient is 2

2

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Is 1.23 greater or less than 1?

Answers

Answer:

1.23 > 1

Step-by-step explanation:

If you have 1, then if there is a decimal point of any number after the 1, the number is greater than 1. Even if the number is 1.0000000000000000000000000000000000000000000000000000000000001, it is still greater than 1.

1.23 is greater than 1

Rewrite the following in terms of ln 2, ln 3, and ln 5. Then use ln 2=0.693, ln 3=1.099, and ln 5=1.609.1. ln 6
2. ln (10/3)
3. ln 30
4. ln 12
5. ln (2/5)
5. ln (5/6)

Answers

$\log_a (b * c)=\log_a b + \log_a c \n \log_a ((b)/(c))=\log_a b-\log_a c \n \log_a b^c=c \log_a b \n \n 1. \n \ln 6=\ln (2 * 3)=\boxed{\ln 2 + \ln 3} \approx 0.693+1.099=\boxed{1.792} \n \n 2. \n \ln ((10)/(3))=\ln ((2 * 5)/(3))=\boxed{\ln 2 + \ln 5 - \ln 3} \approx 0.693+1.609-1.099=\boxed{1.203} \n \n 3. \n \ln 30=\ln (2 * 3 * 5)=\boxed{\ln 2+ \ln 3 + \ln 5} \approx 0.693+ 1.099 + 1.609=\n=\boxed{3.401}$

$4. \n\ln 12=\ln (2^2 * 3)=\ln 2^2 + \ln 3=\boxed{2 \ln 2+ \ln 3} \approx 2 * 0.693+ 1.099= \n =\boxed{2.485} \n \n5. \n\ln ((2)/(5))=\boxed{\ln 2 - \ln 5} \approx 0.693-1.609=\boxed{-0.916} \n \n6. \n\ln ((5)/(6))=\ln ((5)/(2 * 3))=\ln 5-(\ln 2+ \ln 3)=\boxed{\ln 5 - \ln 2 - \ln 3} \approx \n\approx1.609-0.693-1.099=\boxed{-0.183}$

Factor the trinomial in to 2 sets of parentheses
12a squared minus 13a minus 35

Answers

it can't be factored because there are no 2 numbers that when you multiply you get 35 and when you add you get 13.

Can someone please help!! Idk what to do.

Answers

Answer:

3948 members

Step-by-step explanation:

SInce a is the initial amount, a = 2000. b represents growth factor, and the amount increases by 12% every year, so b = 1.12. Since you want to find the value in 6 years, x= 6. Therefore your equation is y = 2000 • 1.12 ^ 6. Plug it into your calculator and you get y = 3947.64, and since they are people you round up to 3948 members.

only chocolate and vanilla ice cream cones are sold at an ice cream store. In one day, the number of chocolate cones sold was 1 more than 4 times the number of vanilla cones sold. A total of 121 cones sold that day

Answers

I just had this question for homework too!

c = 4v + 1
v + c = 121

Now use substitution.

v + 4v + 1 = 121
5v + 1 = 121
5v = 120
v = 24

The answer is 24.

Here's the equation:
4x+1+x = 121. Where x is equal to the amount of vanilla cones.
5x + 1 = 121
5x = 120
x = 24
There were 24 vanilla and 97 chocolate.

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