I REALLY NEED NEED HELP IT DOSENT NEED TO BE A BIG PROCESS A LITTLE ONE!!!!8. Think of another quadratic equation that has two (2) real number solutions. Write the
equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your
answer.
9. Think of another quadratic equation that has one (1) real number solution. Write the
equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your
answer.
10. Think of another quadratic equation that has no (0) real number solutions. Write the
equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your
answer.
Answers
9.) x^2 + 4x + 4 = 0, a = 1, b =4, c =4, discriminant = b^2 - 4ac = (4)^2 - 4(1)(4) = 0, and discriminant = 0 indicates one solution.
10.) x^2 + 1 = 0, a = 1, b =0, c = 1, discriminant = b^2 - 4ac = 0^2 - 4(1)(1) = -4, and discriminant < 0 indicates no real solution.
-2x^2+6x+3=0
-2x^2+6x+ = -3
-2x^2+6x
36/4=9
(-2x^2+6x+9)^2= -3-9
(-2x+9)^2= -12
(-2x)^2= -12-9
(-2x)^2= -18
x= square root of 9
10. same thing above, but not a -2. if you use +2 the answer will be square root of -9.
Related Questions
98 is 35% of what number
What is the solution to the proportion? X/45=8/18 Answers: A. X=16 B. X=20 C. X=35 D. X=101.25
F(x)=x^3+3g(c)=x^2+2 Approximate the solution to the equation f(x)=g(x) using three iterations of successive approximation. Use this graph as a starting point. (It’s not x= -7/8)In the graphing tool, choose the custom option in the Relationship menu to graph the functions f(x) = x^3 + 3 and g(x) = x^2 + 2.Adjust the zoom level of the graph so you can see the point where the two graphed functions intersect. Then, left-click on the point where the functions intersect. The values of the point you click on, rounded to the nearest hundredth, will appear for about 2 seconds.Note: If you’re not using a mouse (or a mouse with left-click ability), perform the equivalent zoom-in action on your device to see the intersection point values rounded to the nearest hundredth.Then, approximate (to the nearest hundredth) the solution of f(x) = g(x) from part A of this question.15 points PLZZZZZ URGENTTT! Urgent maximum wait is 24 hours!
What’s is the answer to 636x73
Answers
7(x + 2) = 9
Then we solve for x. First, distribute:
7x + 14 = 9
Subtract 14 from both sides:
7x = -5
Divide by 7 on both sides:
The number is then -5/7.
y = 4x – 2
A. (0, 3)
B. (1, 2)
C. (2, 1)
D. (0, −2)
Answers
Answer:
B. (1,2)
Step-by-step explanation:
y = –x + 3.......(1)
y = 4x – 2.......(2)
Putting (1) into (2)
-x + 3 = 4x - 2
4x + x = 3 + 2
5x = 5
x = 5/5
x = 1
And putting x = 1 in (1)
y = -x + 3
y = -1 + 3
y = 2
Answer:
B. (1, 2)
Step-by-step explanation:
YEP!! YOUR ANSWER IS B (1, 2)
Putting (1) into (2)
-x + 3 = 4x - 24x + x = 3 + 2
5x = 5
x = 5/5
x = 1
And putting x = 1 in (1)
y = -x + 3
y = -1 + 3
y = 2
Answers
Answer : The Celsius temperature is, 50 degree.
Step-by-step explanation :
Formula used :
where,
c = Celsius temperature
f = Fahrenheit temperature
As we are given that the Fahrenheit temperature is 122 degree. Now we have to determine the Celsius temperature.
Now put the value of Fahrenheit temperature in above formula, we get:
Thus, the Celsius temperature is, 50 degree.
The required Celsius temperature for a Fahrenheit temperature of 122 degrees is 50 degrees Celsius.
To find the Celsius temperature for a Fahrenheit temperature of 122 degrees, we can use the given formula: c = 5(f - 32) / 9.
Substituting the Fahrenheit temperature of 122 degrees into the formula, we have:
c = 5(122 - 32) / 9.
Now we can simplify the expression:
c = 5(90) / 9,
c = 450 / 9,
c = 50.
Therefore, the Celsius temperature for a Fahrenheit temperature of 122 degrees is 50 degrees Celsius.
Learn more about temperature here:
#SPJ6
a. Is the ratio of quarters to dimes still 5:3?
b. If so, illustrate with an example. If not, give a counter-example.
3. You are 13 years old, and your cousin is 19 years old. As you grow older, is your age proportional to your cousin's age? Explain your reasoning
Answers
Answer:
1. The relation is proportional.
2. The ratio of quarters and to dimes will not remain 5 : 3.
3. y = 6 + x, Hence, not proportional.
Step-by-step explanation:
1. I can do 90 sit-ups in 2 minutes and my friend can do 135 sit-ups in 3 minutes.
If we consider t as the time in minutes and n as the number of sit-ups, then we can write (2,90) and (3,135) as two ordered pairs.
So, the relation between t and n will be
⇒ n = 45t
Therefore, the relation is proportional.
2. The initial ratio of quarters to dimes was 5:3. If I add the same number of quarters and dimes to it then,
a) The ratio of quarters and dimes will not still be 5 : 3.
b) Let, the number of quarters was 5 then the number of dimes was 3. {As the ratio was 5 : 3}
Now, we add 3 new quarters and 3 new dimes in the collection. then, finally, the number of quarters will be (5 + 3) = 8 and the number of dimes will become (3 + 3) = 6.
Therefore, the new ratio will become 8 : 6 = 4 : 3 which is not equal to 5 : 3.
3. I am 13 years old, and my cousin is 19 years old.
So, if my age is given by x and that of my cousin is y, then
y - x = 19 - 13
⇒ y - x = 6
⇒ y = 6 + x
This relation will continue as the year passes. So, the relation is not proportional as the relation is not like y = kx. (Answer)
please help me.
Answers
I hope this helps!
Answers
hope that i havee helped you well :)