looking for a common factor
18 : 1, 2, 9, 18
4: 1, 2, 4
so the rows would be 2 rows and their would be 2 photographs and 9 paintings in each
Answer:
Area of the bookmar = 68.56 sq.cm.
Step-by-step explanation:
It is given that the diameter of each circle is the width of the rectangle.
Therefore, each radius = = 2 cm.
Area of the 2 semi circles = 2 × 0.5 × 3.14 ×
= 4 × 3.14
= 12.56 sq.cm.
Now, area of the rectangle = length × width
= 14 × 4
= 56 sq.cm
Area of the bookmark = Area of the rectangular part + 2 × (area of the semicircular part)
= 56 + 12.56
= 68.56 sq.cm.
B. 108pi m3
C. 972pi m3
D. 1292pi m3
Answer:
The answer is B
Step-by-step explanation:
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