Answer is "0.05 mol".
Explanation;
We can do calculation by using a simple formula as
n = m/M
Where, n is the number of moles of the substance (mol), m is the mass of the substance (g) and M is the molar mass of the substance (g/mol).
Here,
n = ?
m = 2.80 g
M = 56.08 g/mol
By substitution,
n = 2.80 g /56.08 g/mol
n = 0.0499 mol ≈ 0.05 mol
B) The weight of the rock.
C) The hardness of the rock.
D) The composition of the rock.
Answer:
Its D.
Explanation:
I just took a usatestprep on it and it had the same question.
Answer:
,dgeh
Explanation:
Bombarding sodium-23 with a
proton produces nuclide X and a neutron. What is nuclide X?
Answers:
magnesium-24
magnesium-23
neon-23
s
odium-24
none of the above
The isotope P
has a half-life of 14.3 days. If a sample originally contained 1.00 g of P,
how much was left after 43 days?
Answers:
0.250 g
0.125 g
0.750 g
0.500 g
Identify X in the reaction
below.
U
+ C
→ Cf
+ X
Answers:
1
alpha particle
3
protons
6
neutrons
6
electrons
A .20 gram sample of C-14 was allowed to decay for 3 half-lives. What mass
of the sample will remain? Carbon-14 has a half life of 5730
years.
Answers:
0.025
0.05
0.1
0
.01
0.05
The isotope Cu
has a half-life of 30 s. If a sample originally contained 48 mg of Cu,
how much time passed before the amount fell to 3 mg?
Answers:
120 s
240s
30 s
60 s(when I did my calculation for the question above, I got 60 seconds)
What radionuclide decays to Fe-56
by beta emission?
Answers:
Fe
Co
Mn
Co
MnHow do I know wat it becomes. I put 57 Co 27 and it's wrong.
The Cf
to Cf
conversion is accompanied by __________.
Answers:
an alpha
emission
a
neutron capture
an electron
capture
an electron releaseI would greatly appreciate your help...ASAP. Thank you.
1 30 seconds
2 32 seconds
3 10 seconds
4 29 seconds
Sugar does not dissolve in water.
The time recorded for Trial 3 may be inaccurate.
His experiment has very low precision.
Answer:
His experiment has very low precision
Explanation:
Precision is how close the answers are together. The answers are increasing in time. So, this makes sence. None of the answers are similar to one another.
B.Exocytosis
C.Osmosis
D.Endocytosis
Answer:
A. Diffusion
Explanation:
A.Diffusion - this is correct. Diffusion is the process where small molecules enter the cell by moving from a high concentration to a low concentration through a semi-permeable membrane.
B.Exocytosis - this is incorrect. Exocytosis is a cell transport mechanism where the cell uses a system of vesicles to transport cargo outside of the cell. The vesicles fuse to the cell membrane and deliver the cargo outside.
C.Osmosis - this is incorrect, osmosis is a type of diffusion specific to water molecules
D.Endocytosis - this is incorrect. Endoocytosis is a cell transport mechanism where the cell uses a system of vesicles to transport cargo into the cell. The cell membrane engulfs the molecules and brings them into the cell via the vesicle