If y is 5 when x is 2.5 and y varies directly with x, find y when x is 10.5
7.5
12.5
20

Answers

Answer 1
Answer: if y is 5 when x is 2.5 and y varies directly with x, find y when x is 10.

The term "y varies directly with x" means that the formula is a direct variation. We need to look for the constant of variation.

y = kx ; where k is the constant of variation.

k = y/x
k = 5/2.5
k = 2

We then use the direct variation formula to get the value of y when x is a certain number.

y = kx
y = 2 * 10
y = 20

Answer 2
Answer:

The value of when y varies directly with x using the direct variation is 20.

In direct variation, the relationship between x and y can be expressed as:

y = k * x

Where k is the constant of variation.

The value of k can be calculated using the data provide in the question

if x = 2.5 then y = 5

5 = k *2.5

The value of k can be calculated by dividing both side by 2.5

k = (5)/(2.5)

k = 2

The value of y can be calculated by substituting  x is 10.

y = 2* 10

y = 20

Therefore, the value of y is 20 when y varies directly with x.

Learn more about direct variation here:

brainly.com/question/33766943

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2. 4xsquared-25

Answers

1.\n(n-2)(3n+7)+2n(2n+3)\n\n=n\cdot3n+n\cdot7-2\cdot3n-2\cdot7+2n\cdot2n+2n\cdot3\n\n=3n^2+7n-6n-14+4n^2+6n\n\n=7n^2+7n-14

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2.\n4x^2-25=(2x)^2-5^2=(2x-5)(2x+5)
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O= n×7= 7n
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Add them together, you get 3n² + n -14.
The second part is 2n(2n+3)
Multiply both numbers inside the bracket by 2n
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Add these terms with the previous ones
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To factor this, we convert it into two expressions that we multiply together (like converting -9 into 3×-3)
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5 × -5= -25
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