give two examples of items that weigh less than 1 ounce and two examples of items that weigh more than 1 ton

Answers

Answer 1

Answer: under an ounce- paper, feather
more than a ton- Elephant, car

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42 decreased by the product of 12 and a number is 6.

Answers

42 - 12x = 6
Solve for 6

12x = 36

x = 3

(3x + 2) (2x - 5) = ax² + kx + n .
What is the value of a - n + k ?

Answers

$(3x + 2) (2x - 5)=ax^2+kx+n \n \n =3x\cdot 2x - 3x\cdot 5 +2\cdot 2x - 2\cdot 5=\n \n=6x^2-15x+4x-10=\n \n=6x^2-11x-10\n \n a=6, \ n=-10 , \ k=-11 \n \na - n + k = 6-(-10)+(-11)=6+10-11= 5$

Gavyn can type 2200 words in 40 minutes. Stephen can type 3850 in 70 minutes.
Richard can type 3000 words in 50 minutes.
Who types at the fastest rate of words per minute?

Answers

Answer:

Richard

Step-by-step explanation:

Gavyn: 55 wpm

Stephen: 55 wpm

Richard: 60 wpm

51 participants went on the 7th grade field trip to the national history museum.2/3 of them rode on a large bus.The rest went in a van. How many were in each vehicle

Answers

51 ÷ 3 = 17
17 were in the van
51 - 17 = 34
34 were in the bus

Hello!,

First: 51÷1/3 would be 17

So 17 kids were in each vehicle!

Darnell's car used 8 gallons of gasoline to travel 340 miles. after a mechanic worked on the car, it used 7 gallons of gasoline to travel 350 miles. If the price of the gasoline was approximately $4.00 per gallon, how much lest to the nearst cent per mile, did it cost to run the car after the mechanic worked on it?

Answers

so, after the mechanic worked on it, it only does 7 gallons for 350miles, how many gallons will it be at that rate, for 340 miles then?

$\bf \begin{array}{ccll}gallons&miles\n\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\n7&350\nx&340\end{array}\implies \cfrac{7}{x}=\cfrac{350}{340}\implies \cfrac{7\cdot 340}{350}=x\implies 6.8=x$

well, each gallon is 4 bucks, for 6.8 gallons that'd be 6.8*4.

we already know that before the mechanic worked on it, it was doing 8gallons for the same 340 miles, and at 4 bucks a gallon that'd be 8*4.

how much is her savings?

$\bf \stackrel{\stackrel{\textit{gallons cost}}{\textit{before being fixed}}}{(8\cdot 4)}\qquad -\qquad \stackrel{\stackrel{\textit{gallons cost}}{\textit{after it was fixed}}}{(6.8\cdot 4)}$

Connor is a prospective student who has been accepted for a $50,000 student loan from two different loan providers. He wants to select the student loan with the lowest total cost. The first loan is a 10-year loan at 4% and the second loan is a 20-year loan at 3%. Both loans compound the interest monthly. Which student loan should Connor select?

Answers

Answer:

To figure out which loan has the lower total cost, we need to calculate the total repayment amount for both loans.

The formula to calculate the monthly payment for a loan is:

P = [r*PV] / [1 - (1 + r)^-n]

where:

P is the monthly payment

r is the monthly interest rate (annual rate / 12)

PV is the present value, i.e., the loan amount

n is the number of payments (months)

For the first loan:

r = 4% / 12 = 0.00333 (approximately)

n = 10 years * 12 = 120 months

PV = $50,000

Plugging these numbers into the formula, we get the monthly payment for the first loan.

For the second loan, we do the same calculation, but with r = 3% / 12 and n = 20 * 12.

After we have the monthly payments, we multiply each by the total number of payments (n) to get the total repayment amount for each loan. The loan with the lower total repayment amount is the one Connor should select.

I hope that helps

Answer:

Connor should select the 10-year loan because it has a lower total cost than the 20-year loan.

Step-by-step explanation: To calculate the total cost of each loan, first find the monthly payment of the loans. Use the formula below to find the monthly payments, where P is the monthly payment, L is the principal amount of the loan, i is the interest rate, and n is the duration of the loan.

P=L×i1−(1+i)−n

The loan amount needed, L, is $50,000 for both loans. Since the interest rate is compounded monthly, the interest rate offered is 4% per year or 0.0412 per month. The time period is 10 years or 120 months. Substituting the values into the formula and converting the interest rate to the monthly rate yields the following.

PP=50,000×0.04121−(1+0.0412)−120≈$506.23

Multiply the monthly payment by the number of months in the loan, 120, to determine the total cost of the loan.

$506.23×120=$60,747.60

Now calculate the monthly cost of the 20-year loan.

PP=50,000×0.03121−(1+0.0312)−240≈$277.30

$277.30×240=$66,552

Since the total cost of the 10-year loan, $60,747.60, is less than the total cost of the 20-year loan, $66,552, Connor should select the 10-year loan.

Your answer:

Connor should select the 20-year loan because it costs less than the 10-year loan.

The 20-year loan has a total cost of $66,552 while the 10-year loan has a total cost of $60,747.60.

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