Log81 1/9= need help with this

Answers

Answer 1
Answer: If it is log 81 base 1/9=x, then you can make the following equation
(1/9)^x=81
x=-2
in this case since 9 squared is 81 and you need to flip the fraction so you add a negative,
Hope this helps. 
Answer 2
Answer: log_(81)(\frac{1}9})
81^(x) = (1)/(9)
ln(81^(x)) = ln((1)/(9))
x\ln(81) = ln((1)/(9))
(x\ln(81))/(ln(81)) = (ln((1)/(9)))/(ln(81))
x = (ln((1)/(3))^(2))/(ln(3)^(4))
x = (2ln((1)/(3)))/(4ln(3))
x = (ln((1)/(3)))/(2ln(3))
x = (-ln(3))/(2ln(3))
x = -(1)/(2)

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3(2x + 1 ) = 2(x + 1) + 1

What is x for number 14.

Answers


It's a right triangle.  So

         (x²) + (10²)  =  (7+x)²

         x²  +  100  =  49 + x² + 14x

That may look ugly, but I'm pretty sure you can handle it from this point.

Wow !  I just noticed that you can subtract  x²  from each side
and not even have to mess with it again.

x^2(x+7)^2=x^2+10^2x^2+14x+49=x^2+10014x+49=10014x=51x=3.64

What is the solution to the system of equations? y = 1/2x-6 and x=-4

Answers

All you have to do is plug -4 for x

y = 1/2 * -4 - 6

y = -8

Solution: (-4, -8)

6a-5b=9 2a+5b=23 using the addition method

Answers

Answer:

a = 4

b = 3

:))

Which function represents the number of seconds, s, in d days? (Hint: The number seconds in a day is 24 × 60 × 60 = 86,400.). The function that represents the number of seconds, s, in d days is f(d) =

Answers

You simply multiply the days with the number of seconds in a day.
f(d) = 86400d.
I hope that this is the answer that you were looking for and it has helped you.
Answer: f(d) = 86,400d

Can you factor 30 X square minus 5X to the third

Answers

30x^2 - 5X^3 = 5*6*x^2 - 5*x^2*x = 5x^2( 6 - x ).

What is the volume of the prisim show below .

8 6 10

Answers

6 * 8 * 10 = 480 is the volume of the prisim.