colton earns $7 per hour plus $1.50 for each pizza delivery. the expression 7h+1.50 can be used to find the total earrings after h hours and d deliveries have been made. how much money will colton earn after working 15 hours and making 8 delivers

Answers

Answer 1

Answer: 7h + 1.50

For 15 hours and 8 delivers, lets find out how much he earns.

7(15) + 1.50(8) = ?

7*15 = 105
1.50*8 = 12

105 + 12 = 117

Answer: He will make $117

Answer 2

Answer: 7h+1.5d
7(15)+1.5(8)
105+12
$117
Hope this helps.

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A. 3
B. 12
C. 64
D. 81

Answers

i assume on this you just multiply 4 * 3 = 12

A student can answer a multiple choice question in 12 ways. 4 x 3 = 12.

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Answers

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Please can someone help me?

Answers

a. The order they finished the race.
b.The names and the times.
c.Nancy,Lionel,and Mavis ran a 5-kilometer race.
d.You will solve the problem by putting the fractions in order from greatest to least.

Hope that helped.

You need to find nancy lionel and marvis time they finished the race from least to greaset i will use the information 5kilograms and 3 cause of girls the information not important is2 second sentencei will add the scoresto see time of race

Solve using quadratic formula x^2+8x=7

Answers

For this case we have the following quadratic equation:

$x ^ 2 + 8x = 7\nx ^ 2 + 8x-7 = 0$

Where:

$a = 1\nb = 8\nc = -7$

We find the solution by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values we have:

$x = \frac {-8 \pm \sqrt {8 ^ 2-4 (1) (- 7)}} {2 (1)}\nx = \frac {-8 \pm \sqrt {64 + 28}} {2}\nx = \frac {-8 \pm \sqrt {92}} {2}\nx = \frac {-8 \pm \sqrt {2 ^ 2 * 23}} {2}\nx = \frac {-8 \pm2 \sqrt {23}} {2}\nx = -4 \pm \sqrt {23}$

Thus, we have two roots:

$x_ {1} = - 4+ \sqrt {23}\nx_ {2} = - 4- \sqrt {23}$

Answer:

$x_ {1} = - 4+ \sqrt {23}\nx_ {2} = - 4- \sqrt {23}$

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Answers

i think you did correct.

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Answers

"Translation" means "move it to a different place".

When you buy a hula-hoop or a frisbee and take it home from the store,
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Translation does not change the shape or the size of a figure. All of its
sides and angles are still the same as they were in the original location.
Wherever it may go, it's still congruent to the picture of it that you took
before it moved.

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