Answer:
Probability of getting sum less than
10 = \frac{30}{36}= \frac{5}{6}
Probability of getting a multiple of 3= \frac{20}{36}= \frac{5}{9}
(A) P(B|A)= \frac{P(B∩A)}{P(A)} = \frac{15/36}{30/36}= \frac{15}{30}=0.5
(B)P(A|B)= \frac{P(A∩B)}{P(B)}= \frac{15/36}{5/9}=0.75
(C) {A∩B} = {3, 6, 9, 12, 15, 18}
(D) {A} = {1, 2, 3, 4, 5 ,6, 7, 8, 9}
-Hope this helps-
Answer: -9
Step-by-step explanation:
f(x)=-5x-4
f(1)=-5(1)-4
=-5-4
f(1) =-9
Answer:
√111 lie between 10 and 11
Step-by-step explanation:
In order to calculate betwwen which values does √111 lie we would have to make the following calculation:
If we calculate 10∧2, the result is=100
If we calculate 11∧2 the result is=121
Therefore, according to that calculations we can be secure that the most certain options of would be that the √111 would be 10<√111<11
Therefore, √111 lie between 10 and 11
Answer:
Correct option: "No, a probability of about 0.20 would be assigned using the relative frequency method if selection is equally likely."
Step-by-step explanation:
The assumption made is that all the 5 different packages are equally likely, i.e. the probability of selecting a package is .
The probability distribution is shown below.
According to the probability distribution:
So it can be seen that the probability of preferring any of the 5 designs are not same.
Thus, the designs are not equally likely.
The correct option is "No, a probability of about 0.20 would be assigned using the relative frequency method if selection is equally likely."
The selection Probability determined using the relative frequency method do not match the assigned probabilities, suggesting that the data do not confirm the belief that one design is as likely to be selected as another.
The given data can be used to calculate the relative frequencies of each package design selected by the consumers.
To determine the selection probabilities using the relative frequency method, divide the number of times a design was preferred by the total number of consumers.
For example, for design 1, the selection probability would be 10/100 = 0.1.
Similarly, for design 2, the selection probability would be 5/100 = 0.05.
The selection probabilities for designs 3, 4, and 5 would be 0.3, 0.4, and 0.15 respectively.
Comparing these probabilities to the assigned probabilities, it can be observed that the assigned probabilities do not match the observed relative frequencies, indicating that the data do not confirm the belief that one design is just as likely to be selected as another.
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Applying the HL congruence theorem, the information marked in the diagram cannot be congruent, so it is FALSE.
The HL congruence theorem states that if the corresponding legs of two right traingles are congruent, and the their hypotenuse are also congruent, then the triangles are congruent.
From the information given, we are not told if the hypotenuse of the right triangles are congruent, so we can't apply the HL congruence theorem to prove they are congruent. The answer is FALSE.
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