What would the decimal number 20 be in binary?

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Answer 1
Answer: 10100 is the answer hope it helps you.


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Calculate the weighted mean from the following sales: $400, $700, $300, $600, $300, $400, $700

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I got $485 ,I added all the numbers together and divided by how many numbers there are in the equation.

Two number cubes are rolled for two seperate events: Event A is the event that the sum of numbers on both cubes is less than 10. Event B is the event that the sum of numbers on both cubes is a multiple of 3. Complete the conditional-probability formula for event B givem thaf event A occurs first by writing A and B in the blanks:

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Answer:

Probability of getting sum less than

10 =  \frac{30}{36}=  \frac{5}{6}

Probability of getting a multiple of 3= \frac{20}{36}= \frac{5}{9}  

(A) P(B|A)= \frac{P(B∩A)}{P(A)} = \frac{15/36}{30/36}= \frac{15}{30}=0.5  

(B)P(A|B)= \frac{P(A∩B)}{P(B)}= \frac{15/36}{5/9}=0.75  

(C) {A∩B} = {3, 6, 9, 12, 15, 18}

(D) {A} = {1, 2, 3, 4, 5 ,6, 7, 8, 9}

-Hope this helps-

Need answer please !!!!!

Answers

Answer: -9

Step-by-step explanation:

f(x)=-5x-4

f(1)=-5(1)-4

    =-5-4

f(1) =-9

Someone help me please​

Answers

Answer:

√111 lie between 10 and 11

Step-by-step explanation:

In order to calculate betwwen which values does √111 lie we would have to make the following calculation:

If we calculate 10∧2, the result is=100

If we calculate 11∧2 the result is=121

Therefore, according to that calculations we can be secure that the most certain options of would be that the √111 would be 10<√111<11

Therefore, √111 lie between 10 and 11

A company that manufactures toothpaste is studying five different package designs. Assuming that one design is just as likely to be selected by a consumer as any other design, what selection probability would you assign to each of the package designs? We would assign a probability of to the design 1 outcome, to design 2, to design 3, to design 4, and to design 5. In an actual experiment, 100 consumers were asked to pick the design they preferred. The following data were obtained. Design Number of Times Preferred 1 10 2 5 3 30 4 40 5 15 Do the data confirm the belief that one design is just as likely to be selected as another? Explain. Yes, the sum of the assigned probabilities is 1. No, a probability of about 0.20 would be assigned using the relative frequency method if selection is equally likely. Yes, the average of the assigned probabilities is 0.20. No, a probability of about 0.50 would be assigned using the relative frequency method if selection is equally likely.

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Answer:

Correct option: "No, a probability of about 0.20 would be assigned using the relative frequency method if selection is equally likely."

Step-by-step explanation:

The assumption made is that all the 5 different packages are equally likely, i.e. the probability of selecting a package is (1)/(5)=0.20.

The probability distribution is shown below.

According to the probability distribution:

  • The probability of a person preferring design 1 is,

        P(X=1)=0.10

  • The probability of a person preferring design 2 is,

        P(X=2)=0.05

  • The probability of a person preferring design 3 is,

        P(X=3)=0.30

  • The probability of a person preferring design 4 is,

        P(X=4)=0.40

  • The probability of a person preferring design 1 is,

        P(X=5)=0.15

So it can be seen that the probability of preferring any of the 5 designs are not same.

Thus, the designs are not equally likely.

The correct option is "No, a probability of about 0.20 would be assigned using the relative frequency method if selection is equally likely."

The selection Probability determined using the relative frequency method do not match the assigned probabilities, suggesting that the data do not confirm the belief that one design is as likely to be selected as another.

The given data can be used to calculate the relative frequencies of each package design selected by the consumers.

To determine the selection probabilities using the relative frequency method, divide the number of times a design was preferred by the total number of consumers.

For example, for design 1, the selection probability would be 10/100 = 0.1.

Similarly, for design 2, the selection probability would be 5/100 = 0.05.

The selection probabilities for designs 3, 4, and 5 would be 0.3, 0.4, and 0.15 respectively.

Comparing these probabilities to the assigned probabilities, it can be observed that the assigned probabilities do not match the observed relative frequencies, indicating that the data do not confirm the belief that one design is just as likely to be selected as another.

Learn more about Probability here:

brainly.com/question/22962752

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Based on the information marked in the diagram, ABC and DEF must be congruent.True Or False?​

Answers

Applying the HL congruence theorem, the information marked in the diagram cannot be congruent, so it is FALSE.

What is the HL Congruence Theorem?

The HL congruence theorem states that if the corresponding legs of two right traingles are congruent, and the their hypotenuse are also congruent, then the triangles are congruent.

From the information given, we are not told if the hypotenuse of the right triangles are congruent, so we can't apply the HL congruence theorem to prove they are congruent. The answer is FALSE.

Learn more about the HL congruence theorem on:

brainly.com/question/2102943