Answer:
I think I explained the circle one before so I'll explain the left question because I wanted some points.
here,
area of circle is πr² which is given= 12 π cm²
so πr²= 12π
r= 2√3
d= 2r= 4√3
AB is diameter so AB= 4√3
The area of the shadedregion is 96.75 cm².
A square is a two-dimensional figure that has four sides and all four sides are equal.
The area of a square is side²
We have,
Square:
Side = 15 cm
Area of a circle = πr²
APC and AQC are arcs of the circles with centers D and B.
If we remove 1/4 of the area of the circle from the circle we get one part of the unshaded region.
There are two similar unshaded parts.
Now,
The area of the unshaded part.
= 2 (side² - (1/4)πr²)
= 2 (15² - 1/4 x 3.14 x 15²)
= 2 x 15² (1 - 0.785)
= 2 x 225 x 0.215
= 96.75 cm²
Thus,
The area of the shadedregion is 96.75 cm².
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move the decimal point two places to the left
multiply by 100
move the decimal point two places to the right
divide by 100
(4w2 - 7w - 6) - (8w2 + 2w - 3)
Choose one answer.
a. -4w2 - 9w - 3
b. 12w2 + 9w + 3
c. -4w2 - 5w - 9
d. 12w2 - 5w - 9
The difference between the polynomials 5x² + 2x + 11 and 7 + 4x - 2x² is 7x² - 2x + 4 option (D)7x² - 2x + 4 is correct.
Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.
The complete question is:
FIND THE DIFFERENCE:
(5x² + 2x + 11) - (7 + 4x - 2x²)
We have two polynomials:
5x² + 2x + 11 and 7 + 4x - 2x²
We have subtract the polynomial 7 + 4x - 2x² from the polynomial 5x² + 2x + 11
= (5x² + 2x + 11) - (7 + 4x - 2x²)
Using distributive property:
= 5x² + 2x + 11 - 7 - 4x + 2x²
= 7x² - 2x + 4
The difference is 7x² - 2x + 4
Thus, the difference between the polynomials 5x² + 2x + 11 and 7 + 4x - 2x² is 7x² - 2x + 4 option (D)7x² - 2x + 4 is correct.
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