c. =
The result of a ∪ (b ∩ c) equals the union of set a with set b, since set b is completely contained within set c. The final answer is {1, 2, 3, 4, 5, 6}.
The question involves concepts of set theory and specifically deals with the union and intersection of sets. The sets given are a = {1, 3, 5}, b = {2, 4, 6}, and c = {1, 2, 3, 4, 5, 6}. We're asked to find the result of a ∪ (b ∩ c), which means we want to determine the union of set a with the intersection of sets b and c. First, we need to find b ∩ c, which are the elements common to both b and c. Since c contains all the elements of b, the intersection b ∩ c is simply b, which is {2, 4, 6}. Now, we take the union of set a with this result, so a ∪ (b ∩ c) = a ∪ b = {1, 2, 3, 4, 5, 6}. Hence, a ∪ (b ∩ c) contains all elements from both set a and set b, as there were no common elements in set a and set b originally.
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Answer:
The largest integer is x+2, or 31.
Step 2: Choose another point on the line, such as (1, 3).
Step 3: Count units to determine the slope ratio. The line runs 1 unit to the right and rises 2 units up, so the slope is.
Step 4: Substitute those values into the point-slope form. y – y1 = m(x – x1) y – 3 = (x – 1) Which of Talia’s steps is incorrect? Step 1 is incorrect because it uses a point that is not on the line. Step 2 is incorrect because it uses a point that is not on the line. Step 3 is incorrect because it shows an incorrect ratio of the slope.
Step 4 is incorrect because it shows an incorrect substitution of (1, 3) into the point-slope form
just took the test the right answer is step 3 is incorrect
Perform the operation. Write the answer in standard form.
1. (6 − i) + (9 + 5i)
2. (7 + 3i) + (11 + 2i)
3. (12 + 4i) − (2 − 15i)
4. (3 − 7i) − (3 + 5i)
5. 7 − (2 − 3i) + 6i
6. −16 + (3 + 4i) − 4i
7. 3i(6 − 5i)
8. −2i(8 + 2i)
9. (−5 + i)(8 − 6i)
10. (3 − 6i)(−1 + 7i)
11. (2 + 5i)(2 − 5i)
12. (−3 − i)(−3 + I)
13. (4 + i) 2
14. (5 − 9i) 2
Thank you again <3
Answer:
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Step-by-step explanation:
Standard form means to put the terms in order based on their exponent (x³ -> x² -> x -> constant)
1. (6 - i) + (9 + 5i)
2. (7 + 3i) + (11 + 2i)
3. (12 + 4i) - (2 - 15i)
4. (3 - 7i) - (3 + 5i)
5. 7 - (2 - 3i) + 6i
6. -16 + (3 + 4i) - 4i
7. 3i(6-5i)
8. -2i(8+2i)
9. (-5 + i)(8 - 6i)
10. (3 - 6i)(-1 + 7i)
11. (2 + 5i)(2 - 5i)
12. (-3 - i)(-3 + i)
13. (4 + i) * 2
14. (5 - 9i) * 2
:p when I first started answering this I thought the parentheses were being multiplied every time and did 100x more work .-.
Hope it helps <3 :D
A: m ≥ -2 and m < 1
B: m ≤ -2 or m > 1
C m ≥ -4/3 and m < 5/3
D: m ≥ - 4/3 or m < 5/3
The solution to the conjunction -5 ≤ 3m + 1 < 4 is m ≥ -2 and m < 1.
To solve the conjunction -5 ≤ 3m + 1 < 4, we need to solve the two inequalities separately. Starting with the left inequality: -5 ≤ 3m + 1. We subtract 1 from both sides: -6 ≤ 3m. Dividing both sides by 3, we get: -2 ≤ m. Next, we solve the right inequality: 3m + 1 < 4. We subtract 1 from both sides: 3m < 3. Dividing both sides by 3, we get: m < 1. Therefore, the solution to the conjunction is m ≥ -2 and m < 1. This means that m is greater than or equal to -2, but less than 1.
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