In a certain dart game, points are awarded for hitting a certain sections of the board. You get 5 points for each hit and lose 3 points for each miss. Each game consists of throwing 10 darts. If one team scores 18 points, how many darts hit the target and how many miss the target?Use substitution or elimination to solve:

t= dart that hit the target
m= darts that miss the target

t+m=10
5t+3m=18

Answers

Answer 1
Answer: so we have
h=hits
m=miss
h+m=10

gain 5 for every hit and lose 3 for every miss
so 5 times number of hit=points from hit
-3 times number of miss=points deducted from miss
add
5h-3m=18
so we have the equations

h+m=10
5h-3m=18

multiply first equation by 3
3h+3m=30
add to first equatio

3h+3m=30
5h-3m=18  +
8h+0m=48


8h=48
divide by 8
h=6
subsitute
h+m=10
6+m=10
subtract 6
m=4


6 hits
4 miss
Answer 2
Answer: Well look at that! The equations are already set up.

Let t= dart that hit the target
Let m= darts that miss the target

t+m=10 This equation is true because you throw 10 darts in one game.
5t+3m=18  This equation is true because the team got 18 points.

Now let's use substitution by solving one variable and substituting what the variable equals into the other equation.
t+m=10
m = 10-t
Now substitute 10-t as "m" in the other equation.
5t + 3(10-t) = 18
5t + 30 -3t = 18
2t = -12
t = -6

Now substitute -6 into the equation m=10-t
m = 10 - (-6)
m = 10 + 6 
m = 16

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There is an "X" drawn on a sheet of paper. One of the smaller angles created is 57 degrees. What are the other 3 angle measures? What are the two typed of angle pairs we need to use?

If n-8=-3, what is 3n?

Answers

Answer:

34

Step-by-step explanation:

A circle has a radius of 11 inches and a central angle AOB that measures 45°. What is the area of sector AOB? Use 3.14 for pi and round your answer to the nearest tenth.a. 47.5 in2
b. 11.9 in2
c. 8.6 in2
d. 4.3 in2

Answers

the answer is A from what my teacher taught me

Answer:

47.461632987542

Step-by-step explanation:

My teacher told me it was this answer, don't know how.

What steps should be taken to calculate the volume of the right triangular prism? Select three options

Answers

Answer:

1st, 4th and 5th options are correct.

Step-by-step explanation:

Please find the attachment.  

We are asked to choose three steps to calculate the volume of the given right triangular prism.

We know that base of triangular prism is triangle. The volume of triangular prism is area of base times height of the prism.

Let us find area of triangular base using area of triangle formula.

A=(1)/(2)bh, where,

b = Base length,

h = Height of triangular base.

Therefore, 1st option is correct.

Upon substituting the base length (8 m) and height (14 m), we will get:

A=(1)/(2)(\text{8 m}* \text{14 m})

A=\text{4 m}* \text{14 m}

A=56\text{ m}^2

Therefore, 4th option is correct.

The volume of the prism would be area of base times height of prism (7 m) as:

\text{Volume of the prism}=(56\text{ m}^2)* 7\text{ m}

\text{Volume of the prism}=392\text{ m}^3

Therefore, 5th option is correct as well.


To calculate the volume of a triangular prism, measure the width and height of a triangular base, then multiply the base by the height by 1/2 to determine the triangle's area. Next, measure the height of the triangular prism and multiply this by the triangle's area to get the volume

Andrew bought 3 baseball cards for $240. After a few months, he got an offer from his friend Jack to buy the first card for double its original value, along with either the second or third card. Andrew decided to sell the first card (at double its original value) along with the second card (at its original price) and got $320 for it. Or, selling the first card (at double its original value) card along with the third card (at its original price) would have only got him $280. What were the original prices for each of the 3 baseball cards?A-(80, 120, 40)

B-(80, 130, 30)

C-(130, 90, 20)

D-(120, 80, 40)

Answers

Answer:

Option D. (120, 80, 40)

Step-by-step explanation:

Let the cost of 3 baseball cards bought by Andrew are $x, $y and $z.

Now we will form the equations to find the unknown values of x, y, and z.

Statement 1 - Andrew bought 3 baseball cards for $240

Equation will be (x + y + z) = 240 --------(1)

Statement 2 - Jack offered a deal to buy the first card for the double of its original value along with the second card for $320.

Equation will be 2x + y = 320 --------(2)

Statement 3 - Jack offered another deal to buy first card for the double of its original value along with third card for $280

Equation formed 2x + z = 280 ------(3)

Now we can solve these equations to get the values of x, y and z.

From equation 2

y = 320 - 2x

From equation 3

z = 280 - 2x

Now we can replace the values of y and z in equation number 1.

Equation 1 becomes after substitution of y and z values

x + (320 - 2x) + (280 - 2x) = 240

Now we will group the similar terms

(x - 2x - 2x) + (320 + 280) = 240

-3x + 600 = 240

-3x = 240 - 600

-3x = - 360

x = (360)/(3)

x = 120

Now  we put x = 120 in the value of y

y = 320 - 2x

y = 320 - 2×120

  = 320 - 240

  = 80

Similarly we put the value x = 120 in value of z

z = 280 - 2x

  = 280 - 2×120

  = 280 - 240

  = 40

So the original values of 3 baseball cards are (120, 80, 40)

Option D. will be the answer.

The Answer is D. Its actually really simple if you add up the answer chouices

A candy machine is filled with candy. The weight of the candy can differ from the desired 84 ounce weight by no more than 0.5 ounces. Solve the absolute value equation given in order to find the heaviest and lightest acceptable weights for the candy machine.|x – 84| = 0.5

Answers

Formula\ for\ absolute\ value\n\n |a|=a,\ for\ a \geq 0\n or\n|a|=-a,\ for\ a<0\n\n|x-84|=0,5\n\n x-84=-0,5\ \ \ or\ \ \ \ x-84=0,5\n x=-0,5+84\ \ \ \ or \ \ \ x=0,5+84\n x=83,5\ \ \ \ \ \ \ \ \ \ \ or\ \ \ x=84,5\n\nThe\ lightes\weight\ is\ 83,5\ ounce\ and\ the\ heaviest\ is\ 84,5\ ounce.

Solve the inequality:

4|x+5| -2 <10

Answers

4 |x + 5| - 2 < 10 4 |x + 5| - 2 < 10
4 |x + 5| < 12 4(x + 5) - 2 < 10
------------ ----- 4x + 20 - 2 < 10
4 4 4x + 18 < 10
|x + 5| < 3 4x < -8
-x - 5 < 3 ---- ------
-x < 8 4 4
---- --- X < -2
-1 -1
X > -8

-8 < x < -2