A radioactive kind of nitrogen has a half-life of 10 minutes. If you start with 64 grams of the substance, how much will be left after 20 minutes

Answers

Answer 1
Answer: There would be 16 grams left after 20 minutes.
64/2 = after ten minutes
= 32
32/2 = after another ten minutes (20 full)
= 16
Answer 2
Answer:

Answer:

30

Step-by-step explanation:

First, find out how many half-lives have passed. Divide the number of minutes by the length of a half-life.

20÷10=2

2 half-lives have passed.

Now figure out how much nitrogen will be left after 2 half-lives have passed. Multiply the starting amount of nitrogen by

1/2

a total of 2 times.

120x1/2 1/2=30

That calculation could also be written with exponents:

120x(1/2)2=30

After 2 half-lives, the amount of nitrogen left will be 30 grams.


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Can someone help me with this problem ? Thxs

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Answers

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What is 3m + 4n - 6n

Answers

Simple,

3m+4n-6n

Simplify your variables....

4n-6n= -2n

Thus,

3m-2n.

That's it, it's simplified...done...out of here...

Thus, your answer is, 3m-2n.

Simplify

3m+4n-6n

= 3m+4n+-6n

Combine like terms

3m+4n+-6n

(3m)+(4n+-6n)

(3m)+(4n-6n)

= 3m -2n


I hope that's help !